We will learn a simple trick to improve our code quality: Reducing If-Else to Boolean Expressions.

**Video Lesson:**

The core challenge of this problem is to simplify code by reducing the use of if-else statements. This is significant because it can make the code more readable, maintainable, and potentially more efficient. Common applications include simplifying decision-making logic in various programming tasks.

Potential pitfalls include misunderstanding the logic and inadvertently changing the behavior of the code. Misconceptions may arise from thinking that all if-else statements can be converted to boolean expressions, which is not always the case.

To solve this problem, we need to identify scenarios where if-else statements can be replaced with boolean expressions. A naive solution might involve directly converting simple if-else statements, but this may not always be optimal. We will explore multiple optimized solutions and discuss why they are better.

Consider a simple if-else statement:

```
int max(int a, int b) {
if (a > b) {
return a;
} else {
return b;
}
}
```

This can be simplified using a boolean expression:

```
int max(int a, int b) {
return (a > b) ? a : b;
}
```

While this is a straightforward example, more complex conditions can also be simplified.

For more complex conditions, consider the following example:

```
boolean isEligible(int age, boolean hasPermission) {
if (age >= 18 && hasPermission) {
return true;
} else {
return false;
}
}
```

This can be simplified to:

```
boolean isEligible(int age, boolean hasPermission) {
return age >= 18 && hasPermission;
}
```

By directly returning the boolean expression, we eliminate the need for if-else statements, making the code cleaner and more concise.

Let's break down the algorithm for converting if-else statements to boolean expressions:

- Identify the condition being checked in the if-else statement.
- Determine the boolean expression that represents the condition.
- Replace the if-else statement with the boolean expression.

For example, in the isEligible method, the condition `age >= 18 && hasPermission`

directly represents the logic being checked, so we can return it as the result.

Here is the Java code for the examples discussed:

```
// Example 1: Simplifying max function
int max(int a, int b) {
// Using ternary operator to simplify if-else
return (a > b) ? a : b;
}
// Example 2: Simplifying eligibility check
boolean isEligible(int age, boolean hasPermission) {
// Directly returning the boolean expression
return age >= 18 && hasPermission;
}
```

The time complexity of these operations is O(1) since they involve simple comparisons and logical operations. The space complexity is also O(1) as no additional space is required.

Consider edge cases such as:

- For the max function, what if both numbers are equal?
- For the eligibility check, what if the age is exactly 18?

These edge cases are handled correctly by the boolean expressions.

To test the solution comprehensively, consider a variety of test cases:

- Simple cases: max(3, 5), max(10, 2)
- Edge cases: max(7, 7), isEligible(18, true), isEligible(17, false)

Use testing frameworks like JUnit to automate the testing process.

When approaching such problems, consider the following tips:

- Break down the logic into simple conditions.
- Look for patterns that can be expressed as boolean expressions.
- Practice by converting various if-else statements to boolean expressions.

Reducing if-else statements to boolean expressions can significantly improve code quality. It makes the code more readable and maintainable. Practice this technique to become proficient in writing cleaner code.

For further reading and practice, consider the following resources: