TL ; DR:
The Math.floor() function returns the largest integer less than or equal to a given number:
System.out.println(Math.floor(3.9)); // Output: 3
System.out.println(Math.floor(5.2)); // Output: 5
System.out.println(Math.floor(7)); // Output: 7
We can use this function if we want to compute the integral part of some division (quotient):
int a = 3;
int b = 7;
System.out.println(Math.floor(20 / a)); // Output: 6
System.out.println(Math.floor(b / a)); // Output: 2
Full lesson:
Remember how we first learn about the division of two integer numbers in primary school?
The quotient is the number of times a division is completed fully, while the remainder is the amount left that doesn't entirely go into the divisor.
Here are some examples:
10 / 2 = quotient 5, remainder 0
15 / 4 = quotient 3, remainder 3
20 / 3 = quotient 6, remainder 2
Floor division
Floor division (//) is a normal division operation except that it returns the integral part of the result (the quotient):
print(10 // 2) # Output: 5
print(15 // 4) # Output: 3
print(20 // 3) # Output: 6
It can also be used with variables:
a = 3
b = 7
print(20 // a) # Output: 6
print(b // a) # Output: 2
Modulo
The modulo operator (%) calculates the remainder of dividing two values:
print(10 % 2) # Output: 0
print(15 % 4) # Output: 3
print(20 % 3) # Output: 2
# Can be used with variables:
a = 2
b = 4
print(b % a) # Output: 0
print(11 % b) # Output: 3
Quotient and remainder
In programming, we combine both these concepts to get the quotient and remainder of some divison:
# Let's divide 26 by 3:
quotient = 26 // 3
remainder = 26 % 3
print(quotient) # Output: 8
print(remainder) # Output: 2
Assignment
Follow the Coding Tutorial and let's practice with quotient and remainder!
Hint
Look at the examples above if you get stuck.
Java's integer division operator / does not floor toward negative infinity — it truncates toward zero. For positive numbers the result is identical, so this difference rarely surfaces until you work with negatives. Java 8 added Math.floorDiv() for true floor behavior that matches Python's //. Understanding the difference prevents subtle bugs in algorithms, circular indexing, and any calculation involving negative values.
// Positive numbers — identical results:
System.out.println(10 / 3); // 3
System.out.println(Math.floorDiv(10, 3)); // 3
// Negative numbers — CRITICAL DIFFERENCE:
System.out.println(-10 / 3); // -3 (truncates toward zero)
System.out.println(Math.floorDiv(-10, 3)); // -4 (floors toward -∞)
// -10 / 3 = -3.333...
// truncate → -3 (toward zero)
// floor → -4 (toward -∞, matching Python's -10 // 3)
Java's % is a remainder operator (result sign matches dividend). Math.floorMod() gives Python-style modulo (result always non-negative when divisor is positive):
// Positive: identical
System.out.println(10 % 3); // 1
System.out.println(Math.floorMod(10, 3)); // 1
// Negative: different
System.out.println(-10 % 3); // -1 (remainder, sign = dividend)
System.out.println(Math.floorMod(-10, 3)); // 2 (modulo, sign = divisor)
// Invariant holds for each pair:
// a / b * b + a % b == a (truncation pair)
// Math.floorDiv(a,b)*b + Math.floorMod(a,b) == a (floor pair)
int a = -10, b = 3;
System.out.println(Math.floorDiv(a,b) * b + Math.floorMod(a,b) == a); // true
// For positive numbers, plain / and % are fine:
int dividend = 26;
int divisor = 3;
int quotient = dividend / divisor; // 8
int remainder = dividend % divisor; // 2
System.out.println("Quotient: " + quotient); // 8
System.out.println("Remainder: " + remainder); // 2
System.out.println((quotient * divisor + remainder) == dividend); // true
// 1. Convert seconds to minutes and seconds:
int totalSeconds = 137;
int minutes = totalSeconds / 60; // 2
int seconds = totalSeconds % 60; // 17
System.out.printf("%dm %ds%n", minutes, seconds); // "2m 17s"
// 2. Binary search midpoint (avoids integer overflow):
int left = 0, right = Integer.MAX_VALUE - 1;
int mid = left + (right - left) / 2; // safe midpoint
// 3. Total pages needed (ceiling division trick):
int totalItems = 95, perPage = 10;
int pages = (totalItems + perPage - 1) / perPage; // 10
System.out.println(pages + " pages");
// 4. Distribute items into rows:
int items = 29, perRow = 4;
int fullRows = items / perRow; // 7
int leftover = items % perRow; // 1
System.out.println(fullRows + " full rows, " + leftover + " left over");
// Use Math.floorDiv() when inputs can be negative:
int offset = -7;
int period = 3;
System.out.println(offset / period); // -2 (truncation)
System.out.println(Math.floorDiv(offset, period)); // -3 (floor — matches Python)
// Circular array indexing — floorMod stays non-negative:
int index = -1;
int size = 5;
System.out.println(Math.floorMod(index, size)); // 4 (wraps to previous position)
System.out.println(index % size); // -1 (not useful for indexing)
/ on integers truncates toward zero — it does NOT floor. Use Math.floorDiv() for true floor behavior (Java 8+).% can return negative values when the dividend is negative — use Math.floorMod() for always-non-negative results./ and % work exactly as expected.(a + b - 1) / b avoids floating-point entirely.With integer division solid, explore Java's full Math class: Math.ceil() and Math.round() for floating-point rounding, Math.abs() for absolute value, and Math.pow() for exponentiation. Apply modulo to algorithm problems: checking even/odd (n % 2 == 0), circular array indexing (Math.floorMod(i, arr.length)), and FizzBuzz.
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