Buggy Code Array Sum in Java

Inside the code editor we've tried to write a function that takes an array nums as argument and prints to the console the sum of all numbers in that list.

So when we called printSum(new int[]{1, 2, 3}), we expected our code to print:

because 1 + 2 + 3 = 6. But it seems like we made some mistakes because when we run our code, it prints:

1
2
3

Assignment:

Your task is to fix our function such that it correctly computes and prints the desired sum.

Understanding the Problem

The core challenge here is to correctly sum all elements of the array and print the result. The initial code seems to be printing each element individually rather than summing them up.

This problem is fundamental in programming and is often used to teach iteration and basic array manipulation. Common applications include calculating totals, averages, and other aggregate statistics.

Potential pitfalls include misunderstanding the requirement to sum the elements and instead performing operations on each element individually.

Approach

To solve this problem, we need to iterate through the array, sum the elements, and then print the result. Let's break down the steps:

Initialize a variable to store the sum.
Iterate through each element of the array.
Add each element to the sum variable.
Print the sum after the loop completes.

Let's first look at a naive approach and then optimize it.

Naive Approach

The naive approach might involve printing each element, which is what the current buggy code does. This is not optimal because it doesn't meet the requirement of summing the elements.

Optimized Approach

The optimized approach involves using a single loop to sum the elements and then printing the result. This approach is efficient with a time complexity of O(n), where n is the number of elements in the array.

Algorithm

Here is a step-by-step breakdown of the optimized algorithm:

Initialize a variable sum to 0.
Loop through each element in the array nums.
Add the current element to sum.
After the loop, print the value of sum.

Code Implementation


public class ArraySum {
    public static void printSum(int[] nums) {
        // Initialize sum to 0
        int sum = 0;
        
        // Iterate through each element in the array
        for (int num : nums) {
            // Add the current element to sum
            sum += num;
        }
        
        // Print the sum
        System.out.println(sum);
    }

    public static void main(String[] args) {
        // Test the function with an example array
        printSum(new int[]{1, 2, 3});
    }
}

In this code:

We initialize sum to 0.
We use a for-each loop to iterate through each element in the array nums.
We add each element to sum.
Finally, we print the value of sum.

Complexity Analysis

The time complexity of this approach is O(n), where n is the number of elements in the array. This is because we iterate through the array once.

The space complexity is O(1) because we only use a single additional variable sum to store the result.

Edge Cases

Consider the following edge cases:

An empty array: The sum should be 0.
An array with one element: The sum should be the value of that element.
An array with negative numbers: The sum should correctly account for negative values.

Examples:


printSum(new int[]{}); // Expected output: 0
printSum(new int[]{5}); // Expected output: 5
printSum(new int[]{-1, -2, -3}); // Expected output: -6

Testing

To test the solution comprehensively, consider the following test cases:

Simple cases with small arrays.
Edge cases as discussed above.
Large arrays to test performance.

Use a testing framework like JUnit to automate these tests.

Thinking and Problem-Solving Tips

When approaching such problems:

Understand the problem requirements clearly.
Break down the problem into smaller steps.
Consider edge cases and test your solution against them.
Practice similar problems to improve your problem-solving skills.

Conclusion

In this blog post, we discussed how to fix a buggy function to correctly sum the elements of an array and print the result. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for developing strong programming skills.

Additional Resources

For further reading and practice, consider the following resources:

Array Sum: Buggy Code in Java (Time Complexity: O(n))