LESSON 158 OF 414 · LOOPING OVER ARRAY INDICES

Employee of the Year V4 - Project in TypeScript

Practice

A whole team is competing. Use a for loop over the arrays to find the most productive employee, then print their 15% bonus.

You start with:

const names: string[] = ["John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"];
const productivities: number[] = [83, 133, 97, 150, 120];
const salaries: number[] = [135000, 335000, 210000, 250000, 180000];

Build:

Alice Chen
Bonus: $37500

Rules:

Index i in all three arrays refers to the same employee.
The winner is whichever employee has the highest productivity. If two employees share the highest productivity, the one listed first wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Start with let bestIndex: number = 0 and loop over the other indices with for (let i: number = 1; i < names.length; i++). Inside the loop, update the best index only when productivities[i] > productivities[bestIndex]: a strict comparison keeps the first employee on a tie.

Use Math.floor to round the 15% down to a whole number: const bonus: number = Math.floor(salaries[bestIndex] * 15 / 100);

+ turns the number into text: console.log("Bonus: $" + bonus);

const names: string[] = ["John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"];
const productivities: number[] = [83, 133, 97, 150, 120];
const salaries: number[] = [135000, 335000, 210000, 250000, 180000];

let bestIndex: number = 0;
for (let i: number = 1; i < names.length; i++) {
    if (productivities[i] > productivities[bestIndex]) {
        bestIndex = i;
    }
}
const bonus: number = Math.floor(salaries[bestIndex] * 15 / 100);
console.log(names[bestIndex]);
console.log("Bonus: $" + bonus);

STEP 1 OF 6

Guided

Ctrl + Enter to check

Employee of the Year V4 - Project in TypeScript

Employee Of The Year V4 in TypeScript