Three employees compete for the award. Use a chained if / else if / else to pick the most productive one and print their 15% bonus.
You start with:
let name1 = "John Doe"
let productivity1 = 83
let salary1 = 135000
let name2 = "Mary Jane"
let productivity2 = 133
let salary2 = 335000
let name3 = "Bob Smith"
let productivity3 = 97
let salary3 = 210000
Build:
Mary Jane Bonus: $50250
Rules:
- The winner is whichever of the three employees has the highest productivity.
- If two or more employees share the highest productivity, the one listed first wins.
- The winner's bonus is 15% of their salary, rounded down to a whole number.
- Print the winner's name on the first line, then
"Bonus: $<amount>"on the second.
Declare
var winnerName: String; var winnerSalary: Int before the if, then use an if / else if / else chain to assign them, so both are still in scope for the prints. Employee 1 wins when its productivity is at least that of both others; if not, employee 2 wins when it is at least employee 3's; otherwise employee 3 wins.
Dividing two whole numbers (
Int) drops the fraction, so winnerSalary * 15 / 100 is already rounded down: let bonus = winnerSalary * 15 / 100
Convert the number with
String(...) (or use \(...) inside the text): print("Bonus: $" + String(bonus))
let name1 = "John Doe"
let productivity1 = 83
let salary1 = 135000
let name2 = "Mary Jane"
let productivity2 = 133
let salary2 = 335000
let name3 = "Bob Smith"
let productivity3 = 97
let salary3 = 210000
var winnerName: String
var winnerSalary: Int
if productivity1 >= productivity2 && productivity1 >= productivity3 {
winnerName = name1
winnerSalary = salary1
} else if productivity2 >= productivity3 {
winnerName = name2
winnerSalary = salary2
} else {
winnerName = name3
winnerSalary = salary3
}
let bonus = winnerSalary * 15 / 100
print(winnerName)
print("Bonus: $" + String(bonus))
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