Build a version of the Unix uniq -d command. Given a list of lines, output only the values whose adjacent run length is greater than one — i.e. lines that actually repeat back-to-back. Each surviving value is printed once (no count, just the value), joined by \n.
Function signature:
def uniqDups(lines: Array[String]): String
Example:
Input: lines = ["a", "a", "b", "c", "c", "c"] Output: "a\nc" When printed: a c
The run of "a"s has length 2 and the run of "c"s has length 3, so both survive. The single "b" is dropped.
Track
prev and count. When the line changes (or after the loop), flush prev only if count > 1. Compare strings with ==, then join the survivors with mkString("\n").
if (count > 1) {
result += prev
}
The full solution:
class Solution {
def uniqDups(lines: Array[String]): String = {
val result = scala.collection.mutable.ListBuffer[String]()
var count = 0
var prev = ""
for (i <- 0 until lines.length) {
if (count > 0 && lines(i) == prev) {
count += 1
} else {
if (count > 1) {
result += prev
}
prev = lines(i)
count = 1
}
}
if (count > 1) {
result += prev
}
result.mkString("\n")
}
}
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