LESSON 160 OF 414 · LOOPING OVER ARRAY INDICES

Top K Brands V3 - Max in Array in Scala

Practice

Many brands sell the same product, stored in two parallel arrays: ratings[i] is the rating of brands[i]. Find the highest-rated brand by scanning with a loop.

You start with:

        val brands = Array("TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith")
        val ratings = Array(4, 5, 3, 5, 4)

Build:

1. MegaCorp (5)

Rules:

Keep the position of the best brand so far in bestIndex, starting at 0, and scan the positions from 1 to the end with a loop.
Update bestIndex only on a strictly higher rating. If two brands share the top rating, the one listed first wins (MegaCorp at position 1, not NeoByte at position 3).
Format the winner as "1. Brand (rating)" and print it with println(...).

Walk the positions with for (i <- 1 until ratings.size) { and compare each rating with the best one so far.

Scala's + on a String and an Int converts the number to text for you.

        val brands = Array("TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith")
        val ratings = Array(4, 5, 3, 5, 4)

        var bestIndex = 0
        for (i <- 1 until ratings.size) {
            if (ratings(i) > ratings(bestIndex)) {
                bestIndex = i
            }
        }
        println("1. " + brands(bestIndex) + " (" + ratings(bestIndex) + ")")

STEP 1 OF 5

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Top K Brands V3 - Max in Array in Scala

Top K Brands V3 in Scala