Use a dictionary (or set) as a fast lookup table to reject well-known weak passwords.
You start with:
val common = Set("password", "123456", "qwerty", "letmein")
val password = "qwerty"
Build:
Password: qwerty Common: True Weak: reject
Rules:
- Print
"Password: "followed by the password. - Look the password up in the set
commonand store the result as a boolean. - Print
"Common: "followed by the boolean. Write it asTrueorFalsewith a capital letter, exactly as in the example (your language's own boolean prints differently, so choose the text yourself). - If it is common, print
"Weak: reject"; otherwise print"Strong: accept".
Try other passwords: with Tr0ub4dor the output is
Password: Tr0ub4dor Common: False Strong: accept
Use a
Set[String] built with Set(...) and call .contains(password).
val common = Set("password", "123456", "qwerty", "letmein")
val password = "qwerty"
println("Password: " + password)
val isCommon = common.contains(password)
println("Common: " + (if (isCommon) "True" else "False"))
if (isCommon) {
println("Weak: reject")
} else {
println("Strong: accept")
}
Free plan: 30 tutor messages. Premium is unlimited.
Saved
Ctrl + Enter to check
