The real cat command can take many files as arguments and prints them one after another. Build that behavior. Given a list of "files" where each file is itself a list of lines, flatten all lines in order and join them with newlines.
A file can be empty (it adds no lines), and the list can hold no files at all; the result is then an empty string.
Function signature:
def concatCat(allLines: List[List[String]]): String
Example:
Input: allLines = [["hello", "world"], ["foo", "bar", "baz"]] Output: "hello\nworld\nfoo\nbar\nbaz" When printed: hello world foo bar baz
Build a flat buffer of
String with a nested loop, preserving order. Then return flat.mkString("\n").
val flat = scala.collection.mutable.ArrayBuffer[String]()
for (fileLines <- allLines) {
for (line <- fileLines) {
flat += line
}
}
return flat.mkString("\n")
The full solution:
class Solution {
def concatCat(allLines: List[List[String]]): String = {
val flat = scala.collection.mutable.ArrayBuffer[String]()
for (fileLines <- allLines) {
for (line <- fileLines) {
flat += line
}
}
return flat.mkString("\n")
}
}
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