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LESSON 89 OF 348 · FREE CODING INTERVIEW QUESTIONS

Minimum Value of Three in Rust

Practice

Given 3 integers A, B and C, return the smallest number.

You are not allowed to use built-in functions such as min

Example 1:

Input: A = 7, B = 4, C = 9
Output: 4

Example 2:

Input: A = 3, B = 8, C = 3
Output: 3


There are three candidates to the solution: A, B and C. We should try out each of them until we find the correct one. How can we check if A is the solution? What should happen for A to be the minimum value?

A is the minimum value if A <= B and A <= C. We can write an if statement checking these conditions and if they hold, return A:
if A <= B and A <= C:
	return A
What if the conditions don't hold and A is not the solution? What should we do next?

We should test B. Similarly, B is the minimum value if B <= A and B <= C. We can write an if statement checking these conditions and if they hold, return B:
if A <= B and A <= C:
	return A
if B <= A and B <= C:
	return B
What if not even B is the solution?

Then, it's clear that C is the solution, so we should return C. We don't even need to check the conditions anymore:
if A <= B and A <= C:
	return A
if B <= A and B <= C:
	return B
return C


While the solution above is very good, we propose another one which is more scalable (i.e. works better for a larger number of values). It involves going throught the numbers and using a variable minVal to store the minimum one found so far:
minVal = A
if B < minVal:
	minVal = B
if C < minVal:
	minVal = C
return minVal
Please watch the video solution for a better understanding of this solution.

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