Compute an end-of-year performance bonus for one employee, then print the employee's name and the bonus.
You start with:
let name = "John Doe";
let productivity = 83;
let salary = 135000;
Build:
John Doe Bonus: $20250
Rules:
- The bonus is 15% of the
salary, rounded down to a whole number. - Print the employee's
nameon the first line. - Print the bonus on the second line as
"Bonus: $<amount>". productivityis not used in this version. It is there for the next versions, where you will compare employees by productivity. (The compiler may warn that it is unused; that is fine.)
Dividing two whole numbers (
i32) drops the fraction, so salary * 15 / 100 is already rounded down: let bonus = salary * 15 / 100;
{} in the format string is replaced by the value: println!("Bonus: ${}", bonus);
let name = "John Doe";
let productivity = 83;
let salary = 135000;
let bonus = salary * 15 / 100;
println!("{}", name);
println!("Bonus: ${}", bonus);
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