LESSON 94 OF 410 · CONDITIONAL STATEMENTS - CHALLENGES

Employee of the Year V3 - Project in Python

Practice

Three employees compete for the award. Use a chained if / elif / else to pick the most productive one and print their 15% bonus.

You start with:

name1 = "John Doe"
productivity1 = 83
salary1 = 135000
name2 = "Mary Jane"
productivity2 = 133
salary2 = 335000
name3 = "Bob Smith"
productivity3 = 97
salary3 = 210000

Build:

Mary Jane
Bonus: $50250

Rules:

The winner is whichever of the three employees has the highest productivity.
If two or more employees share the highest productivity, the one listed first wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Use an if/elif/else chain to pick the winner. Store both their name and their salary (winner_name, winner_salary) in every branch, so the bonus formula stays simple. Employee 1 wins when its productivity is at least that of both others; if not, employee 2 wins when it is at least employee 3's; otherwise employee 3 wins.

Use integer division // so the bonus stays a whole number: bonus = winner_salary * 15 // 100.

Joining text and a number needs str(): print("Bonus: $" + str(bonus))

name1 = "John Doe"
productivity1 = 83
salary1 = 135000
name2 = "Mary Jane"
productivity2 = 133
salary2 = 335000
name3 = "Bob Smith"
productivity3 = 97
salary3 = 210000

if productivity1 >= productivity2 and productivity1 >= productivity3:
    winner_name = name1
    winner_salary = salary1
elif productivity2 >= productivity3:
    winner_name = name2
    winner_salary = salary2
else:
    winner_name = name3
    winner_salary = salary3
bonus = winner_salary * 15 // 100
print(winner_name)
print("Bonus: $" + str(bonus))

STEP 1 OF 9

Guided

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Employee of the Year V3 - Project in Python

Employee Of The Year V3 in Python