Set Matrix Zeroes in JavaScript

Given an m x n matrix of integers matrix, wherever an element is 0, set its entire row and its entire column to 0.

Do it in place: change matrix itself and return nothing.

A matrix is an array of rows, and each row is an array of integers. Rows are numbered from 0, top to bottom, and columns from 0, left to right. Only the zeros that are in matrix at the start count: a cell that becomes 0 doesn't clear its own row and column.

Example 1:

Input: matrix = [
  [1, 1, 1],
  [1, 0, 1],
  [1, 1, 1]
]
Output: [
  [1, 0, 1],
  [0, 0, 0],
  [1, 0, 1]
]
Explanation: The only 0 is in row 1 and column 1, so the whole middle row and the whole middle column become 0.

Example 2:

Input: matrix = [
  [0, 1, 2, 0],
  [3, 4, 5, 2],
  [1, 3, 1, 5]
]
Output: [
  [0, 0, 0, 0],
  [0, 4, 5, 0],
  [0, 3, 1, 0]
]
Explanation: Both zeros are in row 0, in columns 0 and 3. Row 0 becomes all zeros, and so do columns 0 and 3.

Example 3:

Input: matrix = [
  [0, 2, 3, 4],
  [5, 0, 7, 8],
  [9, 10, 11, 12]
]
Output: [
  [0, 0, 0, 0],
  [0, 0, 0, 0],
  [0, 0, 11, 12]
]
Explanation: The zeros in row 0, column 0 and in row 1, column 1 clear rows 0 and 1 and columns 0 and 1. The cells that only became 0 clear nothing more, so 11 and 12 stay.

Constraints:

• m is the number of rows and n the number of columns: 1 <= m, n <= 500
• Every row has the same number of values, n.
• -231 <= matrix[i][j] <= 231 - 1