An AI assistant wrote a product search for this shop: /products/search?q=te finds every product whose name contains te. It built the SQL by joining strings with +:
const word = req.query.q || "";
const rows = db.prepare("SELECT name, price FROM products WHERE name LIKE '%" + word + "%'").all();
The + pastes the visitor's text into the SQL itself. A quote in that text ends the SQL string early, and the rest runs as SQL: Ana's breaks the query, and x' UNION SELECT name, email FROM customers -- answers every customer's name and email, as if they were products. This is SQL injection.
The fix is a placeholder: write ? in the SQL and pass the value beside it, to .all(...). Here it is on another table:
const rows = db.prepare("SELECT name FROM customers WHERE city = ?").all(city);
The SQL text stays the same whatever the visitor types, and the database only compares the value, quotes and all. Your code must give these answers:
GET /products/search?q=te → 200 [{"name": "Notebook", "price": 7}, {"name": "Teapot", "price": 22}]
GET /products/search?q=MUG → 200 [{"name": "Mug", "price": 12}]
GET /products/search?q=Ana's → 200 []
GET /products/search?q=x' UNION SELECT name, email FROM customers -- → 200 []
GET /products/search → 200 [{"name": "Mug", "price": 12}, {"name": "Notebook", "price": 7}, … all 8 products]
Your task: rewrite the handler of GET /products/search. Read q (default ""), build the pattern %word% as a JavaScript string, run the query with LIKE ? and the pattern as its value, and answer the rows as JSON.
Assignment
Follow the Coding Tutorial to rewrite the search route with a placeholder.
Hint
The % signs go into the JavaScript value, not into the SQL: the SQL only says LIKE ?. Pass pattern to .all(...): it gives an array with one object per row, ready for res.json.
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