LESSON 157 OF 410 · LOOPING OVER ARRAY INDICES

Top K Brands V3 - Max in Array in Java

Practice

Many brands sell the same product, stored in two parallel arrays: ratings[i] is the rating of brands[i]. Find the highest-rated brand by scanning with a loop.

You start with:

String[] brands = {"TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith"};
int[] ratings = {4, 5, 3, 5, 4};

Build:

1. MegaCorp (5)

Rules:

Keep the position of the best brand so far in bestIndex, starting at 0, and scan the positions from 1 to the end with a loop.
Update bestIndex only on a strictly higher rating. If two brands share the top rating, the one listed first wins (MegaCorp at position 1, not NeoByte at position 3).
Format the winner as "1. Brand (rating)" and print it with System.out.println(...).

Walk the positions with for (int i = 1; i < ratings.length; i++) { and compare each rating with the best one so far.

Java converts the int to text when you join it to a String with +.

String[] brands = {"TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith"};
int[] ratings = {4, 5, 3, 5, 4};

int bestIndex = 0;
for (int i = 1; i < ratings.length; i++) {
    if (ratings[i] > ratings[bestIndex]) {
        bestIndex = i;
    }
}
System.out.println("1. " + brands[bestIndex] + " (" + ratings[bestIndex] + ")");

STEP 1 OF 5

Guided

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Top K Brands V3 - Max in Array in Java

Top K Brands V3 in Java