LESSON 165 OF 410 · PROJECTS: EVERYDAY PROGRAMS

Password Strength V2 - Has Digit in Java

Practice

Extend the length check with a second rule: the password must also contain at least one digit.

You start with:

String password = "Secret99";

Build:

Length: 8
Has digit: True
Strong

Rules:

Print "Length: " followed by the number of characters.
Loop through each character to set a boolean flag hasDigit, which starts as false and becomes true when a digit is seen.
Print "Has digit: " followed by the flag. Write it as True or False with a capital letter, exactly as in the example (your language's own boolean prints differently, so choose the text yourself).
If the length is at least 8 and hasDigit is true, print Strong; otherwise print Weak.

Try other passwords: with abcdefgh the output is

Length: 8
Has digit: False
Weak

Character.isDigit(c) tests a single char. Use (hasDigit ? "True" : "False") to print a capitalised True/False.

String password = "Secret99";

int length = password.length();
System.out.println("Length: " + length);
boolean hasDigit = false;
for (char c : password.toCharArray()) {
    if (Character.isDigit(c)) {
        hasDigit = true;
    }
}
System.out.println("Has digit: " + (hasDigit ? "True" : "False"));
if (length >= 8 && hasDigit) {
    System.out.println("Strong");
} else {
    System.out.println("Weak");
}

STEP 1 OF 8

Guided

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Password Strength V2 - Has Digit in Java

Password Strength V2 in Java