Calling the Parent with super in Java in Java

TL ; DR:

Inside an overriding method, super.bark() calls the parent's version of bark on the same object. This lets you extend the parent's behavior instead of replacing it.

class Puppy extends Dog {
    public Puppy(String name) { super(name); }
    @Override
    public void bark() {
        super.bark();   // do everything the parent did
        System.out.println("Yip! Said " + name);
    }
}

Why it matters

Overriding a method replaces the parent's behavior. Often you want to extend it instead: keep what the parent did and add something more. A typical example is a save method: the parent writes the row to the database, and a subclass runs the parent's save first and then writes a log line.

Your task

The Puppy class already overrides bark() (note the @Override), but the body is empty. Inside Puppy.bark():

1. call the parent's version with super.bark();, so Woof! I am <name> still prints;
2. then System.out.println("Yip! Said " + name);.

Notes:

• super(name) in the constructor (already written) passes the name up to Dog's constructor; super.bark() does the same for a method.
• name is a public field of Dog, so Puppy can read it directly.

The driver (already written, it runs when you press Run):

Puppy buddy = new Puppy("Buddy");
buddy.bark();
Puppy rex = new Puppy("Rex");
rex.bark();
Dog dog = new Dog("Max");
dog.bark();

• buddy is a Puppy: its bark prints the parent's line, then its own.
• rex is another Puppy: the names come from the object, nothing is hard-coded.
• dog is a plain Dog: its bark is unchanged and prints only the parent's line, with no Yip!.

Expected output:

Woof! I am Buddy
Yip! Said Buddy
Woof! I am Rex
Yip! Said Rex
Woof! I am Max