LESSON 158 OF 404 · LOOPING OVER ARRAY INDICES

Employee of the Year V4 - Project in Go

Practice

A whole team is competing. Use a for loop over the slices to find the most productive employee, then print their 15% bonus.

You start with:

names := []string{"John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"}
productivities := []int{83, 133, 97, 150, 120}
salaries := []int{135000, 335000, 210000, 250000, 180000}

Build:

Alice Chen
Bonus: $37500

Rules:

Index i in all three slices refers to the same employee.
The winner is whichever employee has the highest productivity. If two employees share the highest productivity, the one listed first wins.
The winner's bonus is 15% of their salary, rounded down to a whole number.
Print the winner's name on the first line, then "Bonus: $<amount>" on the second.

Start with bestIndex := 0 and loop over the other indices with for i := 1; i < len(names); i++. Inside the loop, update the best index only when productivities[i] > productivities[bestIndex]: a strict comparison keeps the first employee on a tie.

Dividing two whole numbers (int) drops the fraction, so salaries[bestIndex] * 15 / 100 is already rounded down: bonus := salaries[bestIndex] * 15 / 100

Join text and a number with strconv.Itoa: fmt.Println("Bonus: $" + strconv.Itoa(bonus))

names := []string{"John Doe", "Mary Jane", "Bob Smith", "Alice Chen", "Carlos Diaz"}
productivities := []int{83, 133, 97, 150, 120}
salaries := []int{135000, 335000, 210000, 250000, 180000}

bestIndex := 0
for i := 1; i < len(names); i++ {
    if productivities[i] > productivities[bestIndex] {
        bestIndex = i
    }
}
bonus := salaries[bestIndex] * 15 / 100
fmt.Println(names[bestIndex])
fmt.Println("Bonus: $" + strconv.Itoa(bonus))

STEP 1 OF 6

Guided

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Employee of the Year V4 - Project in Go

Employee Of The Year V4 in Go