LESSON 156 OF 409 · LOOPING OVER ARRAY INDICES

Top K Brands V3 - Max in Array in C++

Practice

Many brands sell the same product, stored in two parallel vectors: ratings[i] is the rating of brands[i]. Find the highest-rated brand by scanning with a loop.

You start with:

vector<string> brands = {"TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith"};
vector<int> ratings = {4, 5, 3, 5, 4};

Build:

1. MegaCorp (5)

Rules:

Keep the position of the best brand so far in bestIndex, starting at 0, and scan the positions from 1 to the end with a loop.
Update bestIndex only on a strictly higher rating. If two brands share the top rating, the one listed first wins (MegaCorp at position 1, not NeoByte at position 3).
Format the winner as "1. Brand (rating)" and print it with cout << ... << endl.

Walk the positions with for (int i = 1; i < (int)ratings.size(); i++) { and compare each rating with the best one so far.

C++ needs to_string(...) to join a number to a string with +.

vector<string> brands = {"TechPro", "MegaCorp", "Quantum", "NeoByte", "Zenith"};
vector<int> ratings = {4, 5, 3, 5, 4};

int bestIndex = 0;
for (int i = 1; i < (int)ratings.size(); i++) {
    if (ratings[i] > ratings[bestIndex]) {
        bestIndex = i;
    }
}
cout << "1. " << brands[bestIndex] << " (" << ratings[bestIndex] << ")" << endl;

STEP 1 OF 5

Guided

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Top K Brands V3 - Max in Array in C++

Top K Brands V3 in C++