LESSON 164 OF 409 · PROJECTS: EVERYDAY PROGRAMS

Password Strength V2 - Has Digit in C++

Practice

Extend the length check with a second rule: the password must also contain at least one digit.

You start with:

string password = "Secret99";

Build:

Length: 8
Has digit: True
Strong

Rules:

Print "Length: " followed by the number of characters.
Loop through each character to set a boolean flag hasDigit, which starts as false and becomes true when a digit is seen.
Print "Has digit: " followed by the flag. Write it as True or False with a capital letter, exactly as in the example (your language's own boolean prints differently, so choose the text yourself).
If the length is at least 8 and hasDigit is true, print Strong; otherwise print Weak.

Try other passwords: with abcdefgh the output is

Length: 8
Has digit: False
Weak

isdigit(c) from <cctype> (already included) works on a char.

string password = "Secret99";

int length = password.length();
cout << "Length: " << length << endl;
bool hasDigit = false;
for (char c : password) {
    if (isdigit(c)) {
        hasDigit = true;
    }
}
cout << "Has digit: " << (hasDigit ? "True" : "False") << endl;
if (length >= 8 && hasDigit) {
    cout << "Strong" << endl;
} else {
    cout << "Weak" << endl;
}

STEP 1 OF 8

Guided

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Password Strength V2 - Has Digit in C++

Password Strength V2 in C++