You get a vector nums. You start at index 0.
Return true if you can get to the last index. Otherwise, return false.
From index i, one jump moves you forward by 1 to nums[i] places. You can make as many jumps as you like. From a 0, you can't jump at all.
Example 1:
Input: nums = [3,0,2,0,1] Output: true Explanation: Jump 2 places, from index 0 to index 2. Then jump 2 places, from index 2 to index 4. There, you are on the last index, 4.
Example 2:
Input: nums = [1,3,0,0,0,2] Output: false Explanation: From index 0, you can only reach index 1. From index 1, you can reach indexes 2, 3 and 4. They all hold 0, so no jump leaves them. Index 5 stays out of reach.
Example 3:
Input: nums = [0] Output: true Explanation: You start on the last index. No jump is needed.
Constraints:
- 1 to 100,000 numbers.
- Each number is a whole number from 0 to 100,000.
Note:
Your solution should run in O(n) time and use O(1) extra space.
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