Find the absolute difference in C++


The absolute difference is a measure of the difference between two numbers but expressed as a positive number.

In other words, it’s taking the difference between two values (x - y) and then calculating the absolute value of the result.

Create a function that takes in two numbers a and b and returns their absolute difference.

Examples:

absDiff(3, 0) ➞ 3

absDiff(0, 3) ➞ 3

absDiff(10, -1) ➞ 11

absDiff(-5, -7) ➞ 2

absDiff(6, -6) ➞ 12

absDiff(1.5, 1.5) ➞ 0

Note:

Do not use the abs() function provided by C++ (it will defeat the purpose of the challenge)


Understanding the Problem

The core challenge of this problem is to compute the absolute difference between two numbers without using the built-in abs() function. The absolute difference is always a non-negative number, regardless of the order of the input numbers.

This problem is significant in various applications such as calculating distances, error margins, and differences in data values. A common pitfall is to forget that the absolute difference must always be positive.

Approach

To solve this problem, we need to consider the following:

We can implement this logic using a simple if statement.

Naive Solution

A naive solution would involve checking the condition and returning the appropriate difference:


// Naive solution to find the absolute difference
double absDiff(double a, double b) {
    if (a < b) {
        return b - a;
    } else {
        return a - b;
    }
}

This solution is straightforward and works correctly, but it can be optimized further.

Optimized Solution

An optimized solution can use the ternary operator to make the code more concise:


// Optimized solution using ternary operator
double absDiff(double a, double b) {
    return (a < b) ? (b - a) : (a - b);
}

This approach is more compact and equally efficient.

Algorithm

Here is a step-by-step breakdown of the algorithm:

  1. Compare the two numbers a and b.
  2. If a is less than b, return b - a.
  3. Otherwise, return a - b.

The optimized solution uses the ternary operator to achieve the same logic in a single line of code.

Code Implementation


// Function to find the absolute difference between two numbers
double absDiff(double a, double b) {
    // Using ternary operator for a concise solution
    return (a < b) ? (b - a) : (a - b);
}

This code is clean, readable, and follows best practices. The ternary operator makes the solution concise without sacrificing clarity.

Complexity Analysis

The time complexity of this solution is O(1) because it involves a constant number of operations regardless of the input values.

The space complexity is also O(1) as no additional space is required beyond the input variables.

Edge Cases

Potential edge cases include:

These edge cases are handled correctly by the provided solution.

Testing

To test the solution comprehensively, consider the following test cases:

absDiff(3, 0) ➞ 3
absDiff(0, 3) ➞ 3
absDiff(10, -1) ➞ 11
absDiff(-5, -7) ➞ 2
absDiff(6, -6) ➞ 12
absDiff(1.5, 1.5) ➞ 0

These test cases cover a range of scenarios, including positive numbers, negative numbers, and zero.

Thinking and Problem-Solving Tips

When approaching such problems, consider the following tips:

Conclusion

In this blog post, we discussed how to find the absolute difference between two numbers without using the built-in abs() function in C++. We explored a naive solution and an optimized solution, provided a detailed algorithm, and analyzed the complexity. We also covered edge cases and testing strategies.

Understanding and solving such problems is crucial for developing strong problem-solving skills. Practice regularly and explore further to enhance your coding abilities.

Additional Resources

For further reading and practice, consider the following resources: