We created two variables to store the original price
of a product in dollars and the discount
percentage applied to that price.
Use these two variables and arithmetic operations to compute and print the price after the discount.
Example:
For example, if price
was 150
and discount
was 10
, the answer would be 135
.
Why? Because the discount is 10%. 10% of 150 dollars is 15 dollars. And 150 - 15 dollars is 135 dollars.
The core challenge of this problem is to correctly apply a percentage discount to a given price. This is a common task in various applications, such as e-commerce platforms, where discounts are frequently applied to products.
Potential pitfalls include incorrect calculations due to misunderstanding percentage operations or arithmetic errors.
To solve this problem, we need to follow these steps:
Let's break down the steps:
discount_amount = (price * discount) / 100 final_price = price - discount_amount
This approach is straightforward and efficient, with a time complexity of O(1) since it involves a constant number of arithmetic operations.
Here is a step-by-step breakdown of the algorithm:
discount_amount = (price * discount) / 100
.final_price = price - discount_amount
.
#include <iostream> // Include the iostream library for input and output
int main() {
double price; // Variable to store the original price
double discount; // Variable to store the discount percentage
// Read the original price and discount percentage from the user
std::cout << "Enter the original price: ";
std::cin >> price;
std::cout << "Enter the discount percentage: ";
std::cin >> discount;
// Calculate the discount amount
double discount_amount = (price * discount) / 100;
// Calculate the final price after applying the discount
double final_price = price - discount_amount;
// Print the final price
std::cout << "The price after discount is: $" << final_price << std::endl;
return 0; // Return 0 to indicate successful execution
}
The time complexity of this solution is O(1) because it involves a constant number of arithmetic operations, regardless of the input values. The space complexity is also O(1) as we are using a fixed amount of extra space for variables.
Consider the following edge cases:
To test the solution comprehensively, consider the following test cases:
Use a variety of test cases, from simple to complex, to ensure the solution works correctly in all scenarios.
When approaching such problems, consider the following tips:
In this blog post, we discussed how to calculate the price after applying a discount using C++. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for various applications, especially in e-commerce. Practice and explore further to enhance your problem-solving skills.
For further reading and practice, consider the following resources: