The n-queens puzzle is the problem of placing n
queens on an n x n
chessboard such that no two queens attack each other.
Given an integer n
, return all distinct solutions to the n-queens puzzle. You may return the answer in any order.
Each solution contains a distinct board configuration of the n-queens' placement, and is represented as an array containing the column for each row of the matrix.
Example:
Input: n = 4 Output: [[1, 3, 0, 2], [2, 0, 3, 1]] Explanation: There exist two distinct solutions to the 4-queens puzzle as shown above
Constraints:
1 <= n <= 9
The core challenge of the N Queens problem is to place n queens on an n x n chessboard such that no two queens can attack each other. This means no two queens can be in the same row, column, or diagonal.
This problem is significant in the field of combinatorial optimization and has applications in various domains such as parallel computing, network design, and more.
Potential pitfalls include misunderstanding the constraints of the problem, such as ensuring that no two queens share the same diagonal.
To solve the N Queens problem, we can use a backtracking approach. The idea is to place queens one by one in different columns, starting from the leftmost column. When placing a queen, we check for clashes with already placed queens. If a clash is found, we backtrack and try the next column.
A naive solution would involve generating all possible configurations of queens on the board and then checking each configuration for validity. This approach is not optimal due to its high time complexity.
The optimized solution uses backtracking to place queens one by one and checks for validity at each step. This reduces the number of configurations that need to be checked.
Here is a step-by-step breakdown of the backtracking algorithm:
#include <iostream>
#include <vector>
using namespace std;
// Function to check if a queen can be placed on board[row][col]
bool isSafe(vector<int> &board, int row, int col) {
for (int i = 0; i < row; ++i) {
if (board[i] == col || abs(board[i] - col) == abs(i - row)) {
return false;
}
}
return true;
}
// Recursive utility function to solve N Queens problem
void solveNQueensUtil(int n, int row, vector<int> &board, vector<vector<int>> &solutions) {
if (row == n) {
solutions.push_back(board);
return;
}
for (int col = 0; col < n; ++col) {
if (isSafe(board, row, col)) {
board[row] = col;
solveNQueensUtil(n, row + 1, board, solutions);
board[row] = -1; // Backtrack
}
}
}
// Function to solve N Queens problem
vector<vector<int>> solveNQueens(int n) {
vector<vector<int>> solutions;
vector<int> board(n, -1);
solveNQueensUtil(n, 0, board, solutions);
return solutions;
}
int main() {
int n = 4;
vector<vector<int>> solutions = solveNQueens(n);
for (const auto &solution : solutions) {
for (int col : solution) {
cout << col << " ";
}
cout << endl;
}
return 0;
}
The time complexity of the backtracking solution is O(N!), where N is the number of queens. This is because we are trying to place each queen in N possible positions, and for each position, we recursively try to place the next queen.
The space complexity is O(N) for the board array used to store the positions of the queens.
Edge cases include:
Our algorithm handles these cases by naturally returning an empty list of solutions when no valid configurations are found.
To test the solution comprehensively, we should include a variety of test cases:
We can use testing frameworks like Google Test for C++ to automate and manage our test cases.
When approaching such problems, it is essential to:
The N Queens problem is a classic example of a combinatorial optimization problem that can be efficiently solved using backtracking. Understanding and solving such problems helps in developing strong problem-solving skills and a deep understanding of algorithms.
We encourage readers to practice and explore further to master these concepts.