Given a string, write a function that returns a coded (h4ck3r 5p34k) version of the string.
In order to work properly, the function should replace all "a"s with 4, "e"s with 3, "i"s with 1, "o"s with 0, and "s"s with 5.
Example 1:
Input: "javascript is cool" Output: "j4v45cr1pt 15 c00l"
Example 2:
Input: "programming is fun" Output: "pr0gr4mm1ng 15 fun"
Example 3:
Input: "become a coder" Output: "b3c0m3 4 c0d3r"
The core challenge of this problem is to iterate through each character of the input string and replace specific characters with their corresponding "h4ck3r sp34k" equivalents. This type of problem is common in text processing and can be useful in various applications such as encoding messages or creating stylized text.
Potential pitfalls include forgetting that strings are immutable in many programming languages, meaning you cannot change a character in place. Instead, you need to build a new string with the desired modifications.
To solve this problem, we can use a straightforward approach:
This approach ensures that we process each character exactly once, making it efficient with a time complexity of O(n), where n is the length of the input string.
Here is a step-by-step breakdown of the algorithm:
result
.c
in the input string.c
is 'a', 'e', 'i', 'o', or 's'.c
matches one of these characters, append the corresponding replacement character to result
.c
does not match any of these characters, append c
itself to result
.result
.
#include <iostream>
#include <string>
std::string toHackerSpeak(const std::string& input) {
std::string result;
for (char c : input) {
if (c == 'a') {
result += '4';
} else if (c == 'e') {
result += '3';
} else if (c == 'i') {
result += '1';
} else if (c == 'o') {
result += '0';
} else if (c == 's') {
result += '5';
} else {
result += c;
}
}
return result;
}
int main() {
std::string input1 = "javascript is cool";
std::string input2 = "programming is fun";
std::string input3 = "become a coder";
std::cout << toHackerSpeak(input1) << std::endl;
std::cout << toHackerSpeak(input2) << std::endl;
std::cout << toHackerSpeak(input3) << std::endl;
return 0;
}
The time complexity of this approach is O(n), where n is the length of the input string. This is because we iterate through each character of the string exactly once.
The space complexity is also O(n) because we create a new string to store the result, which in the worst case will be the same length as the input string.
Potential edge cases include:
Examples:
Input: "" Output: "" Input: "hello" Output: "h3ll0" Input: "aeios" Output: "43105"
To test the solution comprehensively, consider the following test cases:
Using a testing framework like Google Test can help automate and manage these test cases effectively.
When approaching such problems, consider the following tips:
Practicing similar problems and studying different algorithms can help improve your problem-solving skills.
In this blog post, we discussed how to solve the problem of converting a string to "h4ck3r sp34k" in C++. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is important for developing strong problem-solving skills and improving your ability to work with text processing tasks.
We encourage you to practice and explore further to deepen your understanding and proficiency in solving similar problems.
For further reading and practice problems related to this topic, consider the following resources: