Given an array of strings names
that contain first and last names adjacent to each other, return an array containing the full names (separated by one space)
Example:
Input: names = ["John", "Doe", "Andy", "Smith", "Mary", "Johnson"] Output: ["John Doe", "Andy Smith", "Mary Johnson"]
The core challenge of this problem is to pair adjacent elements in the input array to form full names. Each pair of elements represents a first name followed by a last name. The significance of this problem lies in its simplicity and its common application in data processing tasks where names are often split and need to be combined for display or further processing.
Potential pitfalls include not correctly pairing the names or handling arrays with an odd number of elements, which would be an invalid input based on the problem constraints.
To solve this problem, we can iterate through the input array in steps of two, combining each pair of elements into a single string separated by a space. This approach ensures that we correctly pair each first name with its corresponding last name.
Let's break down the approach:
Here is a step-by-step breakdown of the algorithm:
fullNames
to store the full names.names
with a step of 2.fullNames
vector.fullNames
vector.
#include <iostream>
#include <vector>
#include <string>
std::vector<std::string> getFullNames(const std::vector<std::string>& names) {
std::vector<std::string> fullNames;
for (size_t i = 0; i < names.size(); i += 2) {
// Concatenate the first name and last name with a space
std::string fullName = names[i] + " " + names[i + 1];
fullNames.push_back(fullName);
}
return fullNames;
}
int main() {
std::vector<std::string> names = {"John", "Doe", "Andy", "Smith", "Mary", "Johnson"};
std::vector<std::string> result = getFullNames(names);
// Print the result
for (const std::string& name : result) {
std::cout << name << std::endl;
}
return 0;
}
The time complexity of this approach is O(n), where n is the number of elements in the input array. This is because we iterate through the array once, performing a constant amount of work for each pair of elements.
The space complexity is also O(n) because we store the full names in a new vector, which in the worst case will have the same number of elements as the input array.
Potential edge cases include:
To test the solution comprehensively, consider the following test cases:
Example test cases:
Input: names = ["John", "Doe", "Andy", "Smith", "Mary", "Johnson"] Output: ["John Doe", "Andy Smith", "Mary Johnson"] Input: names = [] Output: [] Input: names = ["Alice", "Wonderland"] Output: ["Alice Wonderland"]
When approaching such problems, it's important to:
To improve problem-solving skills, practice solving similar problems and study different algorithms and data structures.
In this blog post, we discussed how to solve the problem of combining adjacent first and last names into full names using a simple and efficient approach. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for developing strong problem-solving skills in programming.
For further reading and practice, consider the following resources: