Sudoku Solver in Python with Time Complexity Analysis


Write a program to solve a Sudoku puzzle by filling the empty cells.

A sudoku solution must satisfy all of the following rules:

  1. Each of the digits 1-9 must occur exactly once in each row.
  2. Each of the digits 1-9 must occur exactly once in each column.
  3. Each of the digits 1-9 must occur exactly once in each of the 9 3x3 sub-boxes of the grid.

The '.' character indicates empty cells.

 

Example 1:



Input: board = [["5","3",".",".","7",".",".",".","."],["6",".",".","1","9","5",".",".","."],[".","9","8",".",".",".",".","6","."],["8",".",".",".","6",".",".",".","3"],["4",".",".","8",".","3",".",".","1"],["7",".",".",".","2",".",".",".","6"],[".","6",".",".",".",".","2","8","."],[".",".",".","4","1","9",".",".","5"],[".",".",".",".","8",".",".","7","9"]]
Output: [["5","3","4","6","7","8","9","1","2"],["6","7","2","1","9","5","3","4","8"],["1","9","8","3","4","2","5","6","7"],["8","5","9","7","6","1","4","2","3"],["4","2","6","8","5","3","7","9","1"],["7","1","3","9","2","4","8","5","6"],["9","6","1","5","3","7","2","8","4"],["2","8","7","4","1","9","6","3","5"],["3","4","5","2","8","6","1","7","9"]]
Explanation: The input board is shown above and the only valid solution is shown below:


 

Constraints:

  • board.length == 9
  • board[i].length == 9
  • board[i][j] is a digit or '.'.
  • It is guaranteed that the input board has only one solution.

Understanding the Problem

The core challenge of solving a Sudoku puzzle lies in ensuring that each number from 1 to 9 appears exactly once in each row, column, and 3x3 sub-box. This problem is significant in various fields such as constraint satisfaction problems, artificial intelligence, and recreational mathematics. A common pitfall is not considering all constraints simultaneously, leading to invalid solutions.

Approach

To solve the Sudoku puzzle, we can use a backtracking algorithm. This approach involves trying to place a number in an empty cell, checking if it leads to a valid solution, and backtracking if it doesn't. Here's a step-by-step breakdown:

  1. Identify the first empty cell.
  2. Try placing each number from 1 to 9 in the cell.
  3. Check if placing the number violates any Sudoku rules.
  4. If it doesn't, move to the next empty cell and repeat the process.
  5. If placing a number leads to a violation, backtrack and try the next number.
  6. Continue this process until the board is completely filled.

Algorithm

Here's a detailed breakdown of the backtracking algorithm:

def solve_sudoku(board):
    def is_valid(board, row, col, num):
        # Check if the number is not repeated in the current row, column, and 3x3 sub-box
        for i in range(9):
            if board[row][i] == num or board[i][col] == num:
                return False
            if board[3 * (row // 3) + i // 3][3 * (col // 3) + i % 3] == num:
                return False
        return True

    def solve(board):
        for row in range(9):
            for col in range(9):
                if board[row][col] == '.':
                    for num in '123456789':
                        if is_valid(board, row, col, num):
                            board[row][col] = num
                            if solve(board):
                                return True
                            board[row][col] = '.'
                    return False
        return True

    solve(board)

Code Implementation

Here's the complete Python code to solve the Sudoku puzzle:

def solve_sudoku(board):
    def is_valid(board, row, col, num):
        # Check if the number is not repeated in the current row, column, and 3x3 sub-box
        for i in range(9):
            if board[row][i] == num or board[i][col] == num:
                return False
            if board[3 * (row // 3) + i // 3][3 * (col // 3) + i % 3] == num:
                return False
        return True

    def solve(board):
        for row in range(9):
            for col in range(9):
                if board[row][col] == '.':
                    for num in '123456789':
                        if is_valid(board, row, col, num):
                            board[row][col] = num
                            if solve(board):
                                return True
                            board[row][col] = '.'
                    return False
        return True

    solve(board)

Complexity Analysis

The time complexity of the backtracking algorithm is O(9^(n*n)), where n is the size of the board (9 in this case). This is because, in the worst case, we might have to try all 9 numbers for each cell. The space complexity is O(n*n) due to the recursion stack.

Edge Cases

Potential edge cases include:

Our algorithm handles these cases by ensuring that it checks all possible numbers for each empty cell and backtracks if necessary.

Testing

To test the solution comprehensively, we can use a variety of test cases:

We can use Python's unittest framework to automate the testing process.

Thinking and Problem-Solving Tips

When approaching such problems, it's essential to:

Conclusion

Solving a Sudoku puzzle using a backtracking algorithm is a classic example of constraint satisfaction problems. Understanding and implementing this algorithm helps in developing problem-solving skills and understanding the importance of considering all constraints simultaneously.

Additional Resources

For further reading and practice problems, consider the following resources: