The absolute difference is a measure of the difference between two numbers but expressed as a positive number.
In other words, it’s taking the difference between two values (x - y
) and then calculating the absolute value of the result.
Create a function that takes in two numbers a
and b
and returns their absolute difference.
Examples:
absDiff(3, 0) ➞ 3 absDiff(0, 3) ➞ 3 absDiff(10, -1) ➞ 11 absDiff(-5, -7) ➞ 2 absDiff(6, -6) ➞ 12 absDiff(1.5, 1.5) ➞ 0
Note:
Do not use the abs()
function provided by Python (it will defeat the purpose of the challenge)
The core challenge of this problem is to compute the absolute difference between two numbers without using the built-in abs()
function. The absolute difference is always a non-negative number, regardless of the order of the inputs.
This problem is significant in various applications such as calculating distances, error margins, and differences in data values. A common pitfall is to forget that the result must always be positive.
To solve this problem, we need to consider the following:
a
is less than b
, the absolute difference is b - a
.a
is greater than or equal to b
, the absolute difference is a - b
.We can use an if
statement to implement this logic.
A naive solution would involve checking the condition and returning the appropriate difference:
def absDiff(a, b):
if a < b:
return b - a
else:
return a - b
While this solution is correct, it can be simplified further using the properties of arithmetic operations.
An optimized solution leverages the fact that the absolute difference can be computed using the formula (a - b) if a >= b else (b - a)
. This can be written more concisely using the max
and min
functions:
def absDiff(a, b):
return max(a, b) - min(a, b)
This approach is more concise and leverages built-in functions for clarity.
Let's break down the optimized algorithm step-by-step:
max(a, b)
.min(a, b)
.Here is the well-commented Python code for the optimized solution:
def absDiff(a, b):
# Calculate the maximum of the two numbers
max_val = max(a, b)
# Calculate the minimum of the two numbers
min_val = min(a, b)
# Return the difference between the maximum and minimum values
return max_val - min_val
# Test cases
print(absDiff(3, 0)) # ➞ 3
print(absDiff(0, 3)) # ➞ 3
print(absDiff(10, -1)) # ➞ 11
print(absDiff(-5, -7)) # ➞ 2
print(absDiff(6, -6)) # ➞ 12
print(absDiff(1.5, 1.5)) # ➞ 0
The time complexity of the optimized solution is O(1) because it involves a constant number of operations regardless of the input values. The space complexity is also O(1) as it uses a fixed amount of space for variables.
Consider the following edge cases:
absDiff(1.5, 1.5)
should return 0
).absDiff(-5, -7)
should return 2
).absDiff(0, 3)
should return 3
).These edge cases are handled correctly by the algorithm as it always computes the positive difference.
To test the solution comprehensively, include a variety of test cases:
def test_absDiff():
assert absDiff(3, 0) == 3
assert absDiff(0, 3) == 3
assert absDiff(10, -1) == 11
assert absDiff(-5, -7) == 2
assert absDiff(6, -6) == 12
assert absDiff(1.5, 1.5) == 0
print("All test cases pass")
test_absDiff()
Using assertions helps ensure that the function behaves as expected for various inputs.
When approaching such problems:
In this blog post, we discussed how to find the absolute difference between two numbers without using the built-in abs()
function in Python. We explored a naive solution and an optimized solution, provided a detailed algorithm, and analyzed the complexity. We also covered edge cases and testing strategies. Understanding and solving such problems is crucial for developing strong problem-solving skills in programming.
For further reading and practice problems related to this topic, consider the following resources: