Given two positive integers A and B, print to the console the first A non-negative numbers that are divisible by B
A number X is divisible by B if X modulo B == 0
Example:
Input: A = 5, B = 3 Output: 3 6 9 12 15 Explanation: The first 5 positive integers that are divisible by 3 are 3, 6, 9, 12 and 15 1 modulo 3 = 1 => not divisible 2 modulo 3 = 2 => not divisible 3 modulo 3 = 0 => divisible 4 modulo 3 = 0 => not divisible 5 modulo 3 = 0 => not divisible 6 modulo 3 = 0 => divisible 7 modulo 3 = 0 => not divisible 8 modulo 3 = 0 => not divisible 9 modulo 3 = 0 => divisible 10 modulo 3 = 0 => not divisible 11 modulo 3 = 0 => not divisible 12 modulo 3 = 0 => divisible 13 modulo 3 = 0 => not divisible 14 modulo 3 = 0 => not divisible 15 modulo 3 = 0 => divisible
The core challenge of this problem is to find the first A non-negative numbers that are divisible by B. This problem is significant in various applications such as generating sequences, filtering data, and more. A common pitfall is to misunderstand the requirement of finding the first A numbers that are divisible by B, not just any A numbers.
To solve this problem, we can start with a naive approach and then optimize it:
The naive approach involves iterating from 1 and checking if each number is divisible by B. We keep a counter of how many numbers we have found so far and stop when we reach A numbers.
An optimized approach leverages the fact that multiples of B are in the form of B, 2B, 3B, ...
. Thus, we can directly generate these multiples without checking each number.
counter * B
.# Naive approach to print the first A multiples of B
def print_multiples_naive(A, B):
count = 0
num = 1
while count < A:
if num % B == 0:
print(num)
count += 1
num += 1
# Example usage
print_multiples_naive(5, 3)
# Optimized approach to print the first A multiples of B
def print_multiples_optimized(A, B):
for i in range(1, A + 1):
print(i * B)
# Example usage
print_multiples_optimized(5, 3)
Naive Approach: The time complexity is O(A * B)
in the worst case because we may need to check up to A * B
numbers to find A
multiples of B
. The space complexity is O(1)
.
Optimized Approach: The time complexity is O(A)
because we directly generate the first A
multiples of B
. The space complexity is O(1)
.
Consider the following edge cases:
To test the solution comprehensively, consider a variety of test cases:
print_multiples_optimized(1, 1)
print_multiples_optimized(0, 5)
print_multiples_optimized(1000, 3)
When approaching such problems, consider the following tips:
In this blog post, we discussed how to solve the problem of printing the first A non-negative numbers divisible by B. We explored both naive and optimized approaches, analyzed their complexities, and provided Python code implementations. Understanding and solving such problems is crucial for developing strong problem-solving skills.
For further reading and practice, consider the following resources: