Given an input array that may contain both positive and negative integers, find the sum of continuous subarray of numbers which has the largest sum.
Example:
Input: nums = [-2, -5, 6, -2, -3, 1, 5, -6]
Output: 7
Explanation: sum([6, -2, -3, 1, 5]) = 7
Your algorithm should run in O(n) time and use at most O(n) extra space.
The core challenge of this problem is to find the subarray with the maximum sum in an array that contains both positive and negative integers. This problem is significant in various fields such as finance (to find the best time to buy and sell stocks) and computer science (for optimization problems).
Potential pitfalls include misunderstanding the requirement for a continuous subarray and not accounting for negative numbers correctly.
To solve this problem, we can use Kadane's Algorithm, which is an efficient way to find the maximum sum subarray in O(n) time complexity. The algorithm works by iterating through the array and keeping track of the maximum sum subarray ending at each position.
A naive solution would involve checking all possible subarrays and calculating their sums, which would result in a time complexity of O(n^2). This is not optimal for large arrays.
Kadane's Algorithm improves upon the naive solution by maintaining two variables: the maximum sum subarray found so far and the maximum sum subarray ending at the current position. This allows us to find the solution in a single pass through the array.
Here is a step-by-step breakdown of Kadane's Algorithm:
max_current
and max_global
to the first element of the array.max_current
to be the maximum of the current element and the sum of max_current
and the current element.max_current
is greater than max_global
, update max_global
.max_global
will contain the maximum sum subarray.def max_subarray_sum(nums):
# Initialize the variables to the first element of the array
max_current = max_global = nums[0]
# Iterate through the array starting from the second element
for num in nums[1:]:
# Update max_current to be the maximum of the current element and the sum of max_current and the current element
max_current = max(num, max_current + num)
# Update max_global if max_current is greater
if max_current > max_global:
max_global = max_current
return max_global
# Example usage
nums = [-2, -5, 6, -2, -3, 1, 5, -6]
print(max_subarray_sum(nums)) # Output: 7
The time complexity of Kadane's Algorithm is O(n) because it involves a single pass through the array. The space complexity is O(1) as it uses a constant amount of extra space.
Potential edge cases include:
Examples:
nums = [-1, -2, -3, -4]
print(max_subarray_sum(nums)) # Output: -1
nums = [1]
print(max_subarray_sum(nums)) # Output: 1
To test the solution comprehensively, include a variety of test cases:
Using a testing framework like unittest
in Python can help automate and organize these tests.
When approaching such problems, it's essential to:
In this blog post, we discussed how to solve the Maximum Sum Subarray problem using Kadane's Algorithm. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for developing strong problem-solving skills in computer science.
For further reading and practice, consider the following resources: