Given an input array that may contain both positive and negative integers, find the sum of continuous subarray of numbers which has the largest sum.
Example:
Input: nums = [-2, -5, 6, -2, -3, 1, 5, -6]
Output: 7
Explanation: sum([6, -2, -3, 1, 5]) = 7
Your algorithm should run in O(n) time and use O(1) extra space.
The problem requires finding the maximum sum of a continuous subarray within a given array of integers, which may include both positive and negative numbers. The solution must be efficient, running in O(n) time and using O(1) extra space.
nums
.Input: nums = [-2, -5, 6, -2, -3, 1, 5, -6]
Output: 7
Explanation: sum([6, -2, -3, 1, 5]) = 7
The core challenge is to find the subarray with the maximum sum efficiently. This problem is significant in various fields such as finance (for finding maximum profit periods) and computer science (for optimizing performance).
Potential pitfalls include misunderstanding the requirement for a continuous subarray and not considering negative numbers correctly.
To solve this problem, we can use Kadane's Algorithm, which is an efficient way to find the maximum sum subarray in linear time.
A naive solution would involve checking all possible subarrays and calculating their sums, which would be very inefficient with a time complexity of O(n^2).
Kadane's Algorithm improves this by maintaining a running sum of the current subarray and updating the maximum sum found so far. The key insight is that if the running sum becomes negative, it should be reset to zero, as a negative sum would decrease the potential maximum sum of any subsequent subarray.
Here is a step-by-step breakdown of Kadane's Algorithm:
max_current
and max_global
to the first element of the array.max_current
to be the maximum of the current element and the sum of max_current
and the current element.max_current
is greater than max_global
, update max_global
.max_global
will contain the maximum sum of the subarray.def max_subarray_sum(nums):
# Initialize max_current and max_global with the first element of the array
max_current = max_global = nums[0]
# Iterate through the array starting from the second element
for num in nums[1:]:
# Update max_current to be the maximum of the current element and the sum of max_current and the current element
max_current = max(num, max_current + num)
# Update max_global if max_current is greater
if max_current > max_global:
max_global = max_current
return max_global
# Example usage
nums = [-2, -5, 6, -2, -3, 1, 5, -6]
print(max_subarray_sum(nums)) # Output: 7
The time complexity of Kadane's Algorithm is O(n) because it involves a single pass through the array. The space complexity is O(1) as it uses only a constant amount of extra space.
Potential edge cases include:
# Edge case examples
print(max_subarray_sum([-1, -2, -3])) # Output: -1
print(max_subarray_sum([5])) # Output: 5
To test the solution comprehensively, consider a variety of test cases:
# Test cases
print(max_subarray_sum([-2, -5, 6, -2, -3, 1, 5, -6])) # Output: 7
print(max_subarray_sum([1, 2, 3, 4, 5])) # Output: 15
print(max_subarray_sum([-1, -2, -3, -4])) # Output: -1
print(max_subarray_sum([10])) # Output: 10
When approaching such problems:
Understanding and solving the maximum sum subarray problem using Kadane's Algorithm is crucial for efficient problem-solving in various applications. Practice and familiarity with such algorithms can significantly enhance your coding and analytical skills.
For further reading and practice:
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