Given a n x m grid filled with integers, find the subsquare with maximum sum among all submatrices.
Example:
Input: [ [ 1, -9, -10, 1], [-1, 10, 10, 1], [ 0, 9, 9, -9], [-1, 3, -1, -1] ] Output: 38 Explanation: 2x2 Submatrix [[10, 10], [9, 9]]
Note: A subsquare is a submatrix having the same number of columns and rows
The core challenge of this problem is to find the subsquare (a submatrix with equal number of rows and columns) within a given n x m grid that has the maximum sum. This problem is significant in various applications such as image processing, data analysis, and financial modeling where finding optimal subregions is crucial.
Potential pitfalls include misunderstanding the definition of a subsquare and not considering all possible subsquares within the grid.
To solve this problem, we need to consider all possible subsquares within the grid and calculate their sums. A naive approach would involve iterating over all possible subsquares and calculating their sums directly, which is computationally expensive.
We can optimize this by using a prefix sum array to quickly calculate the sum of any subsquare. This reduces the time complexity significantly.
The naive solution involves iterating over all possible subsquares and calculating their sums directly. This approach has a time complexity of O(n^3 * m^3), which is not feasible for large grids.
We can use a prefix sum array to optimize the solution. The prefix sum array allows us to calculate the sum of any subsquare in constant time. The steps are as follows:
Here is a step-by-step breakdown of the optimized algorithm:
def max_sum_subsquare(grid):
n = len(grid)
m = len(grid[0])
# Step 1: Compute the prefix sum array
prefix_sum = [[0] * (m + 1) for _ in range(n + 1)]
for i in range(1, n + 1):
for j in range(1, m + 1):
prefix_sum[i][j] = grid[i-1][j-1] + prefix_sum[i-1][j] + prefix_sum[i][j-1] - prefix_sum[i-1][j-1]
max_sum = float('-inf')
# Step 2: Iterate over all possible top-left corners of subsquares
for i in range(1, n + 1):
for j in range(1, m + 1):
# Step 3: Iterate over all possible sizes of subsquares
for size in range(1, min(n - i + 1, m - j + 1) + 1):
# Calculate the sum of the current subsquare using the prefix sum array
total = (prefix_sum[i + size - 1][j + size - 1]
- prefix_sum[i - 1][j + size - 1]
- prefix_sum[i + size - 1][j - 1]
+ prefix_sum[i - 1][j - 1])
# Update the maximum sum
max_sum = max(max_sum, total)
return max_sum
# Example usage
grid = [
[1, -9, -10, 1],
[-1, 10, 10, 1],
[0, 9, 9, -9],
[-1, 3, -1, -1]
]
print(max_sum_subsquare(grid)) # Output: 38
The time complexity of the optimized solution is O(n^3 * m^3) in the worst case, which is a significant improvement over the naive approach. The space complexity is O(n * m) due to the prefix sum array.
Potential edge cases include:
Each algorithm handles these edge cases by considering all possible subsquares and calculating their sums accurately.
To test the solution comprehensively, include a variety of test cases:
Using a testing framework like unittest
in Python can help automate and organize the tests.
When approaching such problems, consider the following tips:
In this blog post, we discussed how to find the maximum sum subsquare in a given grid. We explored both naive and optimized solutions, provided a detailed algorithm, and implemented the solution in Python. Understanding and solving such problems is crucial for developing strong problem-solving skills and optimizing algorithms.
For further reading and practice, consider the following resources: