Given two closed intervals [A1, B1]
and [A2, B2]
, check and return if the two intervals intersect each other.
A closed interval [a, b]
(with a <= b
) denotes the set of real numbers x
with a <= x <= b
.
Two closed intervals are said to intersect if they have common numbers, i.e. that appear in both intervals.
The core challenge of this problem is to determine if two intervals overlap. This is a common problem in computational geometry and has applications in scheduling, computer graphics, and more. A common pitfall is to overcomplicate the solution by considering all possible overlap scenarios, but a simpler approach exists.
To solve this problem, we can think about when the intervals do not intersect. Two intervals do not intersect if one is completely to the left of the other. This can be checked with the conditions:
B1 < A2
: Interval 1 ends before Interval 2 starts.B2 < A1
: Interval 2 ends before Interval 1 starts.If neither of these conditions is true, the intervals must intersect.
A naive solution might involve checking all possible overlap scenarios, but this is unnecessary and inefficient. Instead, we can use the above conditions to simplify our solution.
The optimized solution involves a single if-statement to check the non-intersecting conditions. If either condition is true, the intervals do not intersect; otherwise, they do.
Here is a step-by-step breakdown of the algorithm:
B1 < A2
or B2 < A1
.False
.True
.def intervals_intersect(A1, B1, A2, B2):
# Check if one interval is completely to the left of the other
if B1 < A2 or B2 < A1:
return False
return True
The time complexity of this solution is O(1) because it involves a constant number of operations. The space complexity is also O(1) as no additional space is used.
Consider the following edge cases:
[1, 4]
and [4, 6]
. These should intersect.[1, 2]
and [3, 4]
. These should not intersect.To test the solution comprehensively, consider a variety of test cases:
# Test cases
print(intervals_intersect(1, 6, 3, 8)) # True
print(intervals_intersect(1, 4, 4, 6)) # True
print(intervals_intersect(1, 8, 4, 6)) # True
print(intervals_intersect(4, 6, 1, 3)) # False
print(intervals_intersect(1, 2, 3, 4)) # False
When approaching such problems, consider the simplest conditions that define the problem. Avoid overcomplicating the solution. Practice by solving similar problems and studying different algorithms to improve problem-solving skills.
Understanding and solving interval intersection problems is crucial in many fields. The key is to simplify the problem by focusing on non-intersecting conditions. Practice and exploration of similar problems will enhance your problem-solving abilities.
Our interactive tutorials and AI-assisted learning will help you master problem-solving skills and teach you the algorithms to know for coding interviews.
Start Coding for FREE