Given an integer N, which is a power of 2, return a square of length N filled with the numbers {1, 2, 3, ... N2} following the "Z Pattern".
This consists of recursively traversing the 4 quadrants in the order: upper-left, upper-right, lower-left, lower-right.
Example 1:
Input: N = 2
Output: [
[1, 2],
[3, 4]
]
Example 2:
Input: N = 4
Output:[
[1, 2, 5, 6],
[3, 4, 7, 8],
[9, 10, 13, 14],
[11, 12, 15, 16]
]
The core challenge of this problem is to fill a 2D array in a specific "Z Pattern" order. This pattern involves recursively dividing the array into four quadrants and filling them in a specific sequence: upper-left, upper-right, lower-left, and lower-right. This problem is significant in understanding recursive patterns and matrix manipulations, which have applications in computer graphics, image processing, and more.
To solve this problem, we need to think recursively. The naive approach would be to manually fill the array, but this is not scalable for larger values of N. Instead, we can use a recursive function to handle the filling process.
The naive solution involves iterating through the array and filling it manually. This approach is not optimal because it does not leverage the recursive nature of the problem and can be cumbersome for larger arrays.
The optimized solution involves using a recursive function to fill the array. The function will take the current bounds of the sub-array it needs to fill and the starting number. It will then divide the sub-array into four quadrants and recursively fill each quadrant in the specified order.
Here is a step-by-step breakdown of the algorithm:
// Function to fill the matrix in Z pattern
function fillZPattern(matrix, startRow, startCol, size, startNum) {
// Base case: if the size is 1, fill the single cell
if (size === 1) {
matrix[startRow][startCol] = startNum;
return startNum + 1;
}
// Calculate the size of the sub-quadrants
const halfSize = size / 2;
// Recursively fill the four quadrants
startNum = fillZPattern(matrix, startRow, startCol, halfSize, startNum); // Upper-left
startNum = fillZPattern(matrix, startRow, startCol + halfSize, halfSize, startNum); // Upper-right
startNum = fillZPattern(matrix, startRow + halfSize, startCol, halfSize, startNum); // Lower-left
startNum = fillZPattern(matrix, startRow + halfSize, startCol + halfSize, halfSize, startNum); // Lower-right
return startNum;
}
// Main function to generate the Z pattern matrix
function generateZPattern(N) {
// Initialize an N x N matrix
const matrix = Array.from({ length: N }, () => Array(N).fill(0));
// Start filling the matrix from the top-left corner
fillZPattern(matrix, 0, 0, N, 1);
return matrix;
}
// Example usage:
console.log(generateZPattern(2));
console.log(generateZPattern(4));
The time complexity of this approach is O(N^2) because we are filling each cell of the N x N matrix exactly once. The space complexity is O(N^2) as well, due to the storage required for the matrix.
Since N is always a power of 2, we do not need to handle cases where N is not a power of 2. However, we should consider the smallest possible value of N (which is 1) and ensure our algorithm handles it correctly.
To test the solution comprehensively, we should include a variety of test cases:
We can use console logs or a testing framework like Jest to automate the testing process.
When approaching such problems, it is essential to break down the problem into smaller sub-problems and think recursively. Visualizing the problem with diagrams can also help in understanding the recursive pattern. Practicing similar problems and studying recursive algorithms can improve problem-solving skills.
In this blog post, we discussed how to solve the Z Pattern problem using a recursive approach. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for developing strong problem-solving skills and a deep understanding of algorithms.