Given an array of positive integers nums, return the smallest k values, in any order you want.
Example:
Input: nums = [5, 9, 3, 6, 2, 1, 3, 2, 7, 5], k = 4 Output: [1, 2, 2, 3] Explanation: Smallest number is 1, 2nd smallest is 2, 3rd smallest is 2, 4th smallest is 3
The result can be in any order, [2, 1, 3, 2] is also a correct answer.
For this lesson, your algorithm should run in O(n log maxVal) time and use O(1) extra space.
The core challenge of this problem is to find the smallest k integers from an array of positive integers. This problem is significant in scenarios where we need to filter out the smallest elements from a large dataset, such as in data analysis or competitive programming.
Potential pitfalls include misunderstanding the requirement to return the smallest k values in any order and not optimizing the solution to meet the time complexity constraint.
To solve this problem, we can consider several approaches:
A naive solution would be to sort the array and then return the first k elements. However, this approach has a time complexity of O(n log n), which is not optimal for large datasets.
We can use a min-heap (priority queue) to efficiently find the smallest k elements. The min-heap allows us to maintain the smallest elements seen so far, and it provides O(log k) insertion and deletion times.
Here is a step-by-step breakdown of the optimized algorithm using a min-heap:
// Function to find the smallest k integers
function smallestK(nums, k) {
// Edge case: if k is 0, return an empty array
if (k === 0) return [];
// Create a min-heap using a priority queue
const minHeap = new MinPriorityQueue();
// Insert all elements into the min-heap
for (let num of nums) {
minHeap.enqueue(num);
}
// Extract the smallest k elements
const result = [];
for (let i = 0; i < k; i++) {
result.push(minHeap.dequeue().element);
}
return result;
}
// Example usage
const nums = [5, 9, 3, 6, 2, 1, 3, 2, 7, 5];
const k = 4;
console.log(smallestK(nums, k)); // Output: [1, 2, 2, 3]
The time complexity of this approach is O(n log k) because each insertion and deletion operation in the min-heap takes O(log k) time, and we perform these operations n times. The space complexity is O(k) for storing the k smallest elements in the min-heap.
Potential edge cases include:
To test the solution comprehensively, consider the following test cases:
When approaching such problems, consider the following tips:
In this blog post, we discussed how to find the smallest k integers from an array of positive integers using an optimized approach with a min-heap. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for improving problem-solving skills and preparing for coding interviews.
For further reading and practice, consider the following resources: