Given an array of positive integers nums, return the smallest k values, in any order you want.
Example:
Input: nums = [5, 9, 3, 6, 2, 1, 3, 2, 7, 5], k = 4 Output: [1, 2, 2, 3] Explanation: Smallest number is 1, 2nd smallest is 2, 3rd smallest is 2, 4th smallest is 3
The result can be in any order, [2, 1, 3, 2] is also a correct answer.
For this lesson, your algorithm should run in O(n log k) time and use O(k) extra space.
(There are faster solutions which we will discuss in future lessons)
The core challenge of this problem is to efficiently find the smallest k integers from an array of positive integers. This problem is significant in scenarios where we need to filter out the smallest elements from a large dataset, such as in data analysis, statistics, and competitive programming.
Potential pitfalls include misunderstanding the requirement to return the smallest k values in any order and not optimizing the solution to meet the O(n log k) time complexity constraint.
To solve this problem, we can use a max-heap (priority queue) to keep track of the smallest k elements. The idea is to maintain a heap of size k. As we iterate through the array, we add elements to the heap. If the heap exceeds size k, we remove the largest element (root of the max-heap). This ensures that the heap always contains the k smallest elements.
Here's a step-by-step breakdown of the approach:
Let's break down the algorithm in detail:
// Importing the priority queue library
const { MaxPriorityQueue } = require('@datastructures-js/priority-queue');
/**
* Function to find the smallest k integers in an array
* @param {number[]} nums - Array of positive integers
* @param {number} k - Number of smallest integers to find
* @return {number[]} - Array of k smallest integers
*/
function smallestKIntegers(nums, k) {
// Initialize a max-heap with a capacity of k
const maxHeap = new MaxPriorityQueue({ priority: x => x });
// Iterate through each element in the array
for (const num of nums) {
// Add the current element to the heap
maxHeap.enqueue(num);
// If the heap size exceeds k, remove the largest element
if (maxHeap.size() > k) {
maxHeap.dequeue();
}
}
// Convert the heap to an array and return it
return maxHeap.toArray().map(item => item.element);
}
// Example usage
const nums = [5, 9, 3, 6, 2, 1, 3, 2, 7, 5];
const k = 4;
console.log(smallestKIntegers(nums, k)); // Output: [1, 2, 2, 3]
The time complexity of this approach is O(n log k) because we perform log k operations for each of the n elements in the array. The space complexity is O(k) because the heap stores at most k elements.
Consider the following edge cases:
To test the solution comprehensively, consider the following test cases:
When approaching such problems, consider the following tips:
In this blog post, we discussed how to find the smallest k integers from an array of positive integers using a max-heap. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for improving problem-solving skills and preparing for technical interviews.
For further reading and practice, consider the following resources: