Reverse Array in JavaScript (Time Complexity: O(n))


Understanding the Problem

The core challenge of this problem is to reverse the elements of an array without using any built-in functions like reverse(). This is a common problem that helps in understanding array manipulation and indexing.

Reversing an array is a fundamental operation with applications in various algorithms and data processing tasks. It is essential to understand how to manipulate arrays manually to build a strong foundation in programming.

Potential pitfalls include misunderstanding the indexing or trying to use built-in functions, which are not allowed in this problem.

Approach

To solve this problem, we can use a two-pointer technique. This approach involves swapping elements from the beginning and end of the array until we reach the middle. This method is efficient and has a time complexity of O(n), where n is the number of elements in the array.

Let's break down the approach:

  1. Initialize two pointers: one at the start (left) and one at the end (right) of the array.
  2. Swap the elements at these two pointers.
  3. Move the left pointer one step to the right and the right pointer one step to the left.
  4. Repeat the process until the left pointer is greater than or equal to the right pointer.

Algorithm

Here is a step-by-step breakdown of the algorithm:

  1. Initialize two pointers: left = 0 and right = nums.length - 1.
  2. While left < right:
    • Swap nums[left] and nums[right].
    • Increment left by 1.
    • Decrement right by 1.
  3. Return the modified array.

Code Implementation

function reverseArray(nums) {
  // Initialize two pointers
  let left = 0;
  let right = nums.length - 1;

  // Loop until the two pointers meet in the middle
  while (left < right) {
    // Swap the elements at the left and right pointers
    let temp = nums[left];
    nums[left] = nums[right];
    nums[right] = temp;

    // Move the pointers towards the center
    left++;
    right--;
  }

  // Return the reversed array
  return nums;
}

// Example usage:
const nums = [2, 9, 1, 5, 8];
console.log(reverseArray(nums)); // Output: [8, 5, 1, 9, 2]

Complexity Analysis

The time complexity of this approach is O(n), where n is the number of elements in the array. This is because we are iterating through the array once, swapping elements. The space complexity is O(1) since we are using a constant amount of extra space for the pointers and the temporary variable.

Edge Cases

Consider the following edge cases:

Examples:

// Edge case: empty array
console.log(reverseArray([])); // Output: []

// Edge case: single element array
console.log(reverseArray([1])); // Output: [1]

// Edge case: two elements array
console.log(reverseArray([1, 2])); // Output: [2, 1]

Testing

To test the solution comprehensively, consider a variety of test cases:

Example test cases:

console.log(reverseArray([2, 9, 1, 5, 8])); // Output: [8, 5, 1, 9, 2]
console.log(reverseArray([1, 2, 3, 4, 5])); // Output: [5, 4, 3, 2, 1]
console.log(reverseArray([1])); // Output: [1]
console.log(reverseArray([])); // Output: []
console.log(reverseArray([1, 2])); // Output: [2, 1]

Thinking and Problem-Solving Tips

When approaching such problems, consider the following tips:

Conclusion

Reversing an array is a fundamental problem that helps in understanding array manipulation and indexing. By solving this problem without using built-in functions, you can strengthen your understanding of basic programming concepts and improve your problem-solving skills.

Keep practicing and exploring different problems to enhance your coding abilities.

Additional Resources

For further reading and practice, consider the following resources: