Return Negative in JavaScript with O(1) Time Complexity

Create a function that takes a number as an argument and returns negative of that number. Return negative numbers without any change.

Examples:

negative(4) ➞ -4

negative(15) ➞ -15

negative(-4) ➞ -4

negative(0) ➞ 0

Hints:

You can make use of < operator with an if statement to check if n is negative.

You can add an else statement to handle the case when n is positive.

Understanding the Problem

The core challenge of this problem is to ensure that any given number is returned as its negative equivalent. If the number is already negative, it should be returned as is. This problem is significant in various applications where normalization of values is required, such as in mathematical computations, data processing, and algorithm design.

Potential pitfalls include not handling zero correctly or unnecessarily converting already negative numbers.

Approach

To solve this problem, we can start with a naive approach and then optimize it:

Naive Solution

The naive solution involves checking if the number is positive or negative using an if-else statement. If the number is positive, we return its negative equivalent; otherwise, we return the number as is.

Optimized Solution

An optimized solution can be achieved using a single line of code by leveraging the Math.abs() function. This function returns the absolute value of a number, which we can then negate to ensure the result is always negative.

Algorithm

Here is a step-by-step breakdown of the optimized algorithm:

Take the absolute value of the input number using Math.abs().
Negate the result to ensure it is always negative.
Return the negated value.

Code Implementation

Below is the JavaScript code for both the naive and optimized solutions:

Naive Solution

function negative(n) {
  // Check if the number is positive
  if (n > 0) {
    // Return the negative equivalent
    return -n;
  } else {
    // Return the number as is
    return n;
  }
}

Optimized Solution

function negative(n) {
  // Return the negative equivalent using Math.abs()
  return -Math.abs(n);
}

Complexity Analysis

Both the naive and optimized solutions have a time complexity of O(1) because they perform a constant number of operations regardless of the input size. The space complexity is also O(1) as no additional space is required.

Edge Cases

Potential edge cases include:

Zero: negative(0) ➞ 0
Negative numbers: negative(-5) ➞ -5
Large positive numbers: negative(1000000) ➞ -1000000

Each algorithm handles these edge cases correctly by design.

Testing

To test the solution comprehensively, consider the following test cases:

Simple positive number: negative(4) ➞ -4
Simple negative number: negative(-4) ➞ -4
Zero: negative(0) ➞ 0
Large positive number: negative(1000000) ➞ -1000000

These test cases can be run using any JavaScript testing framework such as Jest or Mocha.

Thinking and Problem-Solving Tips

When approaching such problems, consider the following tips:

Understand the problem requirements and constraints thoroughly.
Start with a simple solution and then look for optimizations.
Consider edge cases and how your solution handles them.
Practice similar problems to improve your problem-solving skills.

Conclusion

In this blog post, we discussed how to solve the problem of returning the negative equivalent of a number in JavaScript. We explored both naive and optimized solutions, analyzed their complexities, and considered edge cases. Understanding and solving such problems is crucial for developing strong problem-solving skills in programming.

Additional Resources

For further reading and practice, consider the following resources: