Print Multiples in JavaScript (Time Complexity: O(A))


Given two positive integers A and B, print to the console the first A non-negative numbers that are divisible by B

A number X is divisible by B if X modulo B == 0

Example:

Input: A = 5, B = 3

Output:
3
6
9
12
15

Explanation:
The first 5 positive integers that are divisible by 3 are
3, 6, 9, 12 and 15
1 modulo 3 = 1 => not divisible
2 modulo 3 = 2 => not divisible
3 modulo 3 = 0 => divisible
4 modulo 3 = 0 => not divisible
5 modulo 3 = 0 => not divisible
6 modulo 3 = 0 => divisible
7 modulo 3 = 0 => not divisible
8 modulo 3 = 0 => not divisible
9 modulo 3 = 0 => divisible
10 modulo 3 = 0 => not divisible
11 modulo 3 = 0 => not divisible
12 modulo 3 = 0 => divisible
13 modulo 3 = 0 => not divisible
14 modulo 3 = 0 => not divisible
15 modulo 3 = 0 => divisible

Understanding the Problem

The core challenge of this problem is to find the first A non-negative numbers that are divisible by B. This problem is significant in various applications such as generating sequences, filtering data, and more. A common pitfall is to iterate through all numbers and check divisibility, which can be inefficient.

Approach

To solve this problem, we can start with a naive approach and then optimize it:

Naive Approach

The naive approach involves iterating through all numbers starting from 1 and checking if each number is divisible by B. We keep a counter to track how many numbers we have found that are divisible by B. This approach is simple but not optimal as it may involve unnecessary checks.

Optimized Approach

An optimized approach leverages the fact that multiples of B are evenly spaced. Instead of checking each number, we can directly generate the multiples of B by multiplying B with an incrementing counter. This approach is more efficient as it avoids unnecessary checks.

Algorithm

Here is a step-by-step breakdown of the optimized algorithm:

  1. Initialize a counter to 1.
  2. Iterate from 1 to A.
  3. In each iteration, multiply the counter by B to get the next multiple of B.
  4. Print the result.
  5. Increment the counter.

Code Implementation

// Function to print the first A non-negative numbers divisible by B
function printMultiples(A, B) {
  // Initialize counter
  let count = 1;
  
  // Loop to print the first A multiples of B
  for (let i = 1; i <= A; i++) {
    // Calculate the multiple
    let multiple = count * B;
    
    // Print the multiple
    console.log(multiple);
    
    // Increment the counter
    count++;
  }
}

// Example usage
printMultiples(5, 3); // Output: 3, 6, 9, 12, 15

Complexity Analysis

The time complexity of the optimized approach is O(A) because we are iterating A times to print the multiples. The space complexity is O(1) as we are using a constant amount of extra space.

Edge Cases

Potential edge cases include:

Examples:

printMultiples(1, 1); // Output: 1
printMultiples(3, 10); // Output: 10, 20, 30

Testing

To test the solution comprehensively, consider a variety of test cases:

Example test cases:

printMultiples(5, 3); // Output: 3, 6, 9, 12, 15
printMultiples(1, 1); // Output: 1
printMultiples(3, 10); // Output: 10, 20, 30

Thinking and Problem-Solving Tips

When approaching such problems, consider the following tips:

Conclusion

In this blog post, we discussed how to solve the problem of printing the first A non-negative numbers divisible by B. We explored both naive and optimized approaches, provided a detailed algorithm, and implemented the solution in JavaScript. Understanding and solving such problems is crucial for developing strong problem-solving skills. Keep practicing and exploring further to improve your abilities.

Additional Resources

For further reading and practice, consider the following resources: