Given an input array of integers and a positive integer k, find out the maximum sum of a contiguous subarray of length exactly k
Example
Input: nums = [5, 6, 1, 2, 6, 6, 4, 3]
, k = 3
Output: 4 6
Explanation: The subarray nums[4...6] has the maximum sum of 16
The core challenge of this problem is to find the maximum sum of any contiguous subarray of length k within the given array. This problem is significant in various applications such as financial analysis, where one might want to find the period with the highest profit.
Potential pitfalls include misunderstanding the requirement for the subarray to be contiguous and not considering edge cases where the array length is less than k.
To solve this problem, we can use a sliding window approach, which is more efficient than a naive solution.
The naive solution involves iterating through all possible subarrays of length k and calculating their sums. This approach has a time complexity of O(n*k), which is not optimal for large arrays.
The sliding window technique allows us to calculate the sum of the subarray in O(1) time after the initial sum calculation. This reduces the overall time complexity to O(n).
Here's how it works:
Let's break down the sliding window algorithm step-by-step:
// Function to find the maximum sum subarray of length k
function maxSumSubarray(nums, k) {
// Initialize the sum of the first k elements
let maxSum = 0;
for (let i = 0; i < k; i++) {
maxSum += nums[i];
}
// Initialize the current sum to the maxSum
let currentSum = maxSum;
// Slide the window from k to the end of the array
for (let i = k; i < nums.length; i++) {
// Update the current sum by adding the current element and subtracting the element k positions behind
currentSum += nums[i] - nums[i - k];
// Update the maxSum if the current sum is greater
maxSum = Math.max(maxSum, currentSum);
}
return maxSum;
}
// Example usage
const nums = [5, 6, 1, 2, 6, 6, 4, 3];
const k = 3;
console.log(maxSumSubarray(nums, k)); // Output: 16
The time complexity of the sliding window approach is O(n) because we only pass through the array once. The space complexity is O(1) as we are using a constant amount of extra space.
Consider the following edge cases:
To test the solution comprehensively, consider the following test cases:
When approaching such problems, it's essential to:
In this blog post, we discussed how to find the maximum sum subarray of length k using a sliding window approach. This method is efficient and easy to implement, making it a valuable tool for solving similar problems.
Understanding and practicing such problems can significantly enhance your problem-solving skills and prepare you for coding interviews and real-world applications.
For further reading and practice, consider the following resources: