Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
Example 1:
Input: [100, 4, 200, 1, 3, 2]
Output: 4
Explanation: Longest consecutive sequence is [1, 2, 3, 4]
.
Therefore its length is 4.
Example 2:
Input: [0, 2, 0, 1, 2, 3, 1]
Output: 4
Explanation: Longest consecutive sequence is [0, 1, 2, 3]
.
Therefore its length is 4.
Note that we count each value once, even tho values 0, 1 and 2 appear 2 times each in nums
For this lesson, your algorithm should run in O(n log n) time and use O(1) extra space.
(There are faster solutions which we will discuss in future lessons)
The problem requires finding the length of the longest consecutive elements sequence in an unsorted array of integers.
Input: [100, 4, 200, 1, 3, 2] Output: 4 Explanation: Longest consecutive sequence is [1, 2, 3, 4]. Therefore its length is 4.
The core challenge is to identify the longest sequence of consecutive integers in an unsorted array. This problem is significant in various applications such as data analysis, where identifying trends or patterns in data is crucial.
Potential pitfalls include handling duplicate elements and ensuring the solution is efficient in terms of time complexity.
To solve this problem, we can start with a naive approach and then move to more optimized solutions.
A naive solution would involve sorting the array and then finding the longest consecutive sequence. However, this approach has a time complexity of O(n log n) due to the sorting step.
We can optimize the solution by using a set to store the elements and then iterate through the array to find the longest consecutive sequence. This approach has a time complexity of O(n) and uses O(n) extra space.
1. Sort the array.
2. Iterate through the sorted array and find the longest consecutive sequence.
3. Keep track of the maximum length of consecutive sequences found.
Here is a step-by-step breakdown of the algorithm:
// Function to find the length of the longest consecutive sequence
function longestConsecutive(nums) {
if (nums.length === 0) return 0;
// Sort the array
nums.sort((a, b) => a - b);
let maxLength = 1;
let currentLength = 1;
for (let i = 1; i < nums.length; i++) {
// If the current element is the same as the previous one, skip it
if (nums[i] === nums[i - 1]) continue;
// If the current element is consecutive to the previous one
if (nums[i] === nums[i - 1] + 1) {
currentLength++;
} else {
// Update the maximum length and reset the current length
maxLength = Math.max(maxLength, currentLength);
currentLength = 1;
}
}
// Return the maximum length
return Math.max(maxLength, currentLength);
}
// Example usage
console.log(longestConsecutive([100, 4, 200, 1, 3, 2])); // Output: 4
console.log(longestConsecutive([0, 2, 0, 1, 2, 3, 1])); // Output: 4
The time complexity of the optimized solution is O(n log n) due to the sorting step. The space complexity is O(1) as we are not using any extra space apart from a few variables.
Potential edge cases include:
Input: [] Output: 0 Input: [1, 1, 1, 1] Output: 1 Input: [-1, -2, -3, 0, 1, 2, 3] Output: 7
To test the solution comprehensively, we can use a variety of test cases, from simple to complex. Here are some examples:
Test Cases: console.log(longestConsecutive([100, 4, 200, 1, 3, 2])); // Output: 4 console.log(longestConsecutive([0, 2, 0, 1, 2, 3, 1])); // Output: 4 console.log(longestConsecutive([])); // Output: 0 console.log(longestConsecutive([1, 1, 1, 1])); // Output: 1 console.log(longestConsecutive([-1, -2, -3, 0, 1, 2, 3])); // Output: 7
When approaching such problems, it is essential to:
In this blog post, we discussed how to find the length of the longest consecutive sequence in an unsorted array of integers. We started with a naive solution and then optimized it. We also covered the complexity analysis, edge cases, and testing strategies. Understanding and solving such problems is crucial for improving problem-solving skills and preparing for coding interviews.
For further reading and practice problems, you can refer to the following resources: