Given a tree encoded as a string, for every node, compute the sum of its subtree values and return the sums tree encoded as a string.
For example, the following tree is given as an encoded string "1{2{3,4},5{6}}" :
1 / \ 2 5 / \ \ 3 4 6After computing the sums, the tree will look like the following:
21 / \ 9 11 / \ \ 3 4 6Therefore the output will be "21{9{3,4},11{6}}"
Example 1:
Input: "1{2{3,4},5{6}}" Output: "21{9{3,4},11{6}}"
Example 2:
Input: "1{1,1{1,1,1},1}" Output: "7{1,4{1,1,1},1}"
The core challenge of this problem is to parse the encoded tree string, compute the sum of each node's subtree, and then re-encode the tree with these sums. This problem is significant in scenarios where hierarchical data needs to be processed and summarized, such as in organizational structures or file systems.
Potential pitfalls include correctly parsing the tree structure and ensuring that the sums are computed accurately for each subtree.
To solve this problem, we need to:
A naive solution might involve manually parsing the string and computing sums, but this would be error-prone and inefficient. Instead, we can use a more structured approach with recursion.
We can use a recursive approach to parse the tree and compute the sums. This approach is more efficient and easier to implement correctly.
Here is a step-by-step breakdown of the algorithm:
/**
* Function to parse the encoded tree string and compute subtree sums.
* @param {string} str - The encoded tree string.
* @returns {string} - The encoded tree string with subtree sums.
*/
function encodedTreeSums(str) {
// Helper function to parse the tree string
function parseTree(s, index) {
let num = 0;
while (index < s.length && !isNaN(s[index])) {
num = num * 10 + parseInt(s[index]);
index++;
}
let node = { value: num, children: [] };
if (index < s.length && s[index] === '{') {
index++;
while (index < s.length && s[index] !== '}') {
let child;
[child, index] = parseTree(s, index);
node.children.push(child);
if (s[index] === ',') index++;
}
index++;
}
return [node, index];
}
// Helper function to compute subtree sums
function computeSums(node) {
if (!node) return 0;
let sum = node.value;
for (let child of node.children) {
sum += computeSums(child);
}
node.value = sum;
return sum;
}
// Helper function to encode the tree back to string
function encodeTree(node) {
if (!node) return '';
let result = node.value.toString();
if (node.children.length > 0) {
result += '{' + node.children.map(encodeTree).join(',') + '}';
}
return result;
}
// Parse the tree, compute sums, and encode back to string
let [root, _] = parseTree(str, 0);
computeSums(root);
return encodeTree(root);
}
// Example usage:
console.log(encodedTreeSums("1{2{3,4},5{6}}")); // Output: "21{9{3,4},11{6}}"
console.log(encodedTreeSums("1{1,1{1,1,1},1}")); // Output: "7{1,4{1,1,1},1}"
The time complexity of this solution is O(n), where n is the number of nodes in the tree. This is because we visit each node exactly once to compute the sums. The space complexity is also O(n) due to the recursion stack and the tree structure.
Potential edge cases include:
Examples of edge cases and their expected outputs:
Input: "" Output: "" Input: "1" Output: "1"
To test the solution comprehensively, we should include a variety of test cases:
We can use JavaScript testing frameworks like Jest or Mocha to automate the testing process.
When approaching such problems, it's important to:
Practicing similar problems and studying algorithms can help improve problem-solving skills.
In this blog post, we discussed how to solve the problem of computing subtree sums for an encoded tree string. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for developing strong problem-solving skills in programming.
For further reading and practice, consider the following resources: