Inside the code editor we've tried to write a function that takes an array nums
as argument and returns true
if there exists at least one positive (greater than zero) number in the array; returns false
otherwise.
So when we called the function for [-1, 2, 3]
, we expected our code to print:
Array has positive numbers
but it seems like we made some mistakes because when we run our code, it prints:
Array doesn't have positive numbers
Assignment:
Your task is to fix our function.
The core challenge here is to identify if there is at least one positive number in the given array. This is a common problem in array manipulation and has applications in data validation, filtering, and more. A potential pitfall is not correctly iterating through the array or misinterpreting the conditions for checking positive numbers.
To solve this problem, we need to iterate through the array and check each element to see if it is greater than zero. If we find such an element, we can immediately return true
. If we finish the iteration without finding any positive numbers, we return false
.
A naive solution would involve iterating through the array and using a flag to indicate if a positive number has been found. This approach is straightforward but can be optimized.
An optimized solution would involve iterating through the array and returning true
as soon as we find a positive number. This reduces unnecessary checks once the condition is met.
Here is a step-by-step breakdown of the optimized algorithm:
true
immediately.false
.function hasPositiveNumber(nums) {
// Iterate through each element in the array
for (let i = 0; i < nums.length; i++) {
// Check if the current element is greater than zero
if (nums[i] > 0) {
// If a positive number is found, return true
return true;
}
}
// If no positive number is found, return false
return false;
}
// Test cases
console.log(hasPositiveNumber([-1, 2, 3])); // Expected output: true
console.log(hasPositiveNumber([-1, -2, -3])); // Expected output: false
console.log(hasPositiveNumber([0, 0, 0])); // Expected output: false
console.log(hasPositiveNumber([1, -1, -2])); // Expected output: true
The time complexity of this solution is O(n)
, where n
is the number of elements in the array. This is because in the worst case, we need to check each element once. The space complexity is O(1)
as we are not using any extra space that scales with the input size.
Potential edge cases include:
false
.false
.false
.true
.These edge cases are handled by the current implementation.
To test the solution comprehensively, we should include a variety of test cases:
Using a testing framework like Jest can help automate and manage these tests effectively.
When approaching such problems, it's important to:
Practicing similar problems and studying different algorithms can help improve problem-solving skills.
In this blog post, we discussed how to identify if an array contains at least one positive number. We explored a naive solution and an optimized solution, provided a detailed algorithm, and implemented the solution in JavaScript. We also analyzed the complexity and discussed edge cases and testing strategies. Understanding and solving such problems is crucial for improving coding skills and preparing for technical interviews.
For further reading and practice, consider the following resources: