Given an array of integers nums and another integer value, check if value occurs in nums.
If the value occurs in nums, return true; otherwise return false.
Examples:
contains([1, 2, 4, 5], 4) -> true contains([-1, 2, -4, 0, 10], 7) -> false
Note:
Do not use builtin functions such as includes()
, it would defy the whole purpose of the challenge. Write the whole code yourself.
The core challenge of this problem is to determine if a given integer exists within an array of integers. This is a fundamental problem in computer science with applications in search algorithms, data validation, and more. A common pitfall is to use built-in functions like includes()
, which simplifies the task but does not help in understanding the underlying algorithm.
To solve this problem, we can iterate through the array and check each element to see if it matches the given value. This is a straightforward approach but ensures we understand the basics of array traversal and comparison.
The naive solution involves iterating through each element of the array and checking if it matches the given value. This approach has a time complexity of O(n), where n is the number of elements in the array. While this is not the most optimized solution for very large arrays, it is sufficient for this problem.
Given the constraints of the problem, the naive solution is already optimal. We cannot improve the time complexity beyond O(n) for this problem because we need to check each element at least once.
Here is a step-by-step breakdown of the algorithm:
true
.false
.function contains(nums, value) {
// Iterate through each element in the array
for (let i = 0; i < nums.length; i++) {
// Check if the current element matches the given value
if (nums[i] === value) {
return true; // Return true if a match is found
}
}
return false; // Return false if no match is found
}
// Test cases
console.log(contains([1, 2, 4, 5], 4)); // true
console.log(contains([-1, 2, -4, 0, 10], 7)); // false
The time complexity of this approach is O(n), where n is the number of elements in the array. This is because we may need to check each element once. The space complexity is O(1) since we are not using any additional space that scales with the input size.
Consider the following edge cases:
false
.true
as soon as it finds the first match.Examples:
contains([], 1) -> false contains([1], 1) -> true contains([1, 2, 3, 1], 1) -> true
To test the solution comprehensively, consider a variety of test cases:
Example test cases:
console.log(contains([1, 2, 4, 5], 4)); // true console.log(contains([-1, 2, -4, 0, 10], 7)); // false console.log(contains([], 1)); // false console.log(contains([1], 1)); // true console.log(contains([1, 2, 3, 1], 1)); // true
When approaching such problems, consider the following tips:
In this blog post, we discussed how to determine if a given integer exists within an array of integers. We explored a straightforward approach with a time complexity of O(n) and provided a detailed explanation of the algorithm and code implementation. Understanding and solving such problems is crucial for developing strong problem-solving skills in computer science.
For further reading and practice, consider the following resources: