Calling Functions: Quiz in Java - Time Complexity: O(1)


Quiz: What would this code produce if we were to copy-paste it in a code editor and run it?

void greetCoder() {
	System.out.println("Hello!");
	System.out.println("Let's code!");
}

void mainFunction() {
	greetCoder();
	greetCoder();
}

Options:


Important Note:

Do not use an actual code editor to get the answer! It would defy the whole purpose of the quiz!


Instructions:

Pick your answer and assign variable answer in the code editor with that answer.

For example, if you think the answer to the quiz is B, write String answer = "B"; in the code editor and press Validate Solution!.

Understanding the Problem

The core challenge of this problem is to understand the flow of function calls in Java. Specifically, we need to determine what the output will be when the mainFunction is executed. This involves understanding how the greetCoder function is called and how many times it is executed.

Approach

To solve this problem, we need to follow these steps:

  1. Identify the functions defined in the code.
  2. Understand the sequence of function calls when mainFunction is executed.
  3. Determine the output of each function call.

Let's break down the code:

void greetCoder() {
	System.out.println("Hello!");
	System.out.println("Let's code!");
}

void mainFunction() {
	greetCoder();
	greetCoder();
}

When mainFunction is called, it calls greetCoder twice. Each call to greetCoder prints "Hello!" followed by "Let's code!". Therefore, the output will be:

Hello!
Let's code!
Hello!
Let's code!

Algorithm

The algorithm for determining the output is straightforward:

  1. Call mainFunction.
  2. Within mainFunction, call greetCoder twice.
  3. Each call to greetCoder prints "Hello!" and "Let's code!".
  4. Combine the outputs of both calls to get the final result.

Code Implementation

Here is the Java code for the given problem:

public class Main {
    // Function to greet the coder
    void greetCoder() {
        System.out.println("Hello!");
        System.out.println("Let's code!");
    }

    // Main function that calls greetCoder twice
    void mainFunction() {
        greetCoder();
        greetCoder();
    }

    // Main method to run the program
    public static void main(String[] args) {
        Main main = new Main();
        main.mainFunction();
    }
}

Complexity Analysis

The time complexity of this problem is O(1) because the number of function calls is constant and does not depend on any input size. The space complexity is also O(1) as no additional space is used that scales with input size.

Edge Cases

There are no significant edge cases for this problem as the function calls and their outputs are straightforward and do not depend on any variable input.

Testing

To test the solution, you can run the provided Java code in any Java IDE or online compiler. The expected output should be:

Hello!
Let's code!
Hello!
Let's code!

Thinking and Problem-Solving Tips

When approaching similar problems, it is essential to understand the flow of function calls and the sequence of operations. Breaking down the problem into smaller parts and analyzing each function's behavior can help in understanding the overall output.

Conclusion

In this blog post, we discussed how to determine the output of a sequence of function calls in Java. We broke down the problem, analyzed the function calls, and provided a detailed solution with code implementation. Understanding such problems is crucial for mastering function calls and flow control in programming.

Additional Resources