Sum of Two Numbers in C++ with O(1) Time Complexity


In this lesson we will introduce you to how challenges work and how to make the most out of them. Let's check your first coding challenge:


Sum of Two Numbers

You are given two numbers a and b and you should return their sum.

Examples:

Input: a = 4, b = 9

Output: 13

Explanation:
The sum of a and b is 4 + 9, which is 13.

This is the challenge statement. It explains what the challenge asks us to do and provides some examples to make sure we understand the statement.

Each challenge gives us some input and asks us to write some code that successfully takes that input and uses it to produce some desired output.

In this case, the input is two numbers a and b and the output is their sum.


The class:

If you look at the code editor, you will see that everything is wrapped up inside a class:

class Solution {
public:
    
};

You don't need to know anything about classes or that public: keyword at this point, we will study them in future lessons. Just leave that code untouched.


The function:

Inside this class, we will always be provided with a function. Inside this function is where we should write our solution.

In our case the function is:

int sum(int a, int b) {
    // Your solution goes here!
}

Parameters and return:

This method's parameters will always match the input described in the challenge's statement. In our case, the parameters are a and b, the two numbers we are given.

The method should return a value which represents the desired output described in the challenge's statement. In our case, it should return a + b.


Assignment:

Follow the Coding Tutorial and let's solve our first coding challenge: Sum of Two Numbers


Understanding the Problem

The core challenge of this problem is to correctly implement a function that takes two integers as input and returns their sum. This is a fundamental problem that helps in understanding how to handle basic arithmetic operations in programming.

Significance and common applications include:

Potential pitfalls and misconceptions:

Approach

To solve this problem, we need to think about the simplest way to add two numbers. The naive solution is straightforward: simply return the sum of the two numbers.

Initial naive solution:

int sum(int a, int b) {
    return a + b;
}

This solution is optimal for this problem as it directly addresses the requirement with a single arithmetic operation.

Algorithm

Step-by-step breakdown of the algorithm:

  1. Take two integers as input parameters.
  2. Compute their sum using the addition operator.
  3. Return the computed sum.

This algorithm is efficient with a time complexity of O(1) since it performs a constant-time operation.

Code Implementation

class Solution {
public:
    // Function to return the sum of two numbers
    int sum(int a, int b) {
        // Return the sum of a and b
        return a + b;
    }
};

Explanation of key parts of the code:

Complexity Analysis

The time complexity of this solution is O(1) because the addition operation takes constant time.

The space complexity is also O(1) as no additional space is required beyond the input parameters.

Edge Cases

Potential edge cases include:

These edge cases are handled correctly by the algorithm as it simply adds the two numbers.

Testing

To test the solution comprehensively, consider the following test cases:

Testing frameworks like Google Test can be used to automate these tests.

Thinking and Problem-Solving Tips

When approaching such problems:

To improve problem-solving skills, practice similar problems and study different algorithms.

Conclusion

In this blog post, we discussed how to solve the problem of summing two numbers in C++. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for developing strong programming skills.

Keep practicing and exploring further to enhance your problem-solving abilities.

Additional Resources

For further reading and practice problems, consider the following resources: