Given an input string s, reverse the order of the words.
A word is defined as a sequence of non-space characters. The words in s will be separated by one space for simplicity.
Return a string of the words in reverse order concatenated by a single space.
Example:
Input: input = "sky is blue" Output: "blue is sky"
The core challenge of this problem is to reverse the order of words in a given string. This is a common problem in text processing and has applications in various fields such as natural language processing and data formatting. A potential pitfall is to mistakenly reverse the characters within the words instead of reversing the order of the words themselves.
To solve this problem, we can follow these steps:
Let's discuss a naive solution and then move on to an optimized approach.
A naive solution would involve manually iterating through the string to identify words, storing them in a list, and then reversing the list. This approach, while straightforward, can be inefficient due to the manual handling of string operations.
An optimized solution leverages built-in string manipulation functions to split, reverse, and join the words efficiently. This reduces the complexity and makes the code cleaner and more maintainable.
Here is a step-by-step breakdown of the optimized algorithm:
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
std::string reverseWords(const std::string &s) {
std::istringstream iss(s);
std::vector<std::string> words;
std::string word;
// Split the string into words
while (iss >> word) {
words.push_back(word);
}
// Reverse the order of words
std::reverse(words.begin(), words.end());
// Join the words back into a single string
std::ostringstream oss;
for (size_t i = 0; i < words.size(); ++i) {
if (i != 0) {
oss << " ";
}
oss << words[i];
}
return oss.str();
}
int main() {
std::string input = "sky is blue";
std::string output = reverseWords(input);
std::cout << output << std::endl; // Output: "blue is sky"
return 0;
}
The time complexity of this solution is O(n), where n is the length of the input string. This is because we are iterating through the string to split it into words and then iterating through the list of words to reverse and join them. The space complexity is also O(n) due to the storage of words in a vector.
Consider the following edge cases:
Examples:
Input: input = "" Output: "" Input: input = " hello world " Output: "world hello"
To test the solution comprehensively, consider the following test cases:
Using a testing framework like Google Test can help automate and manage these tests effectively.
When approaching such problems, it's important to:
Practicing similar problems and studying algorithms can significantly improve problem-solving skills.
In this blog post, we discussed how to reverse the words in a string using C++. We covered the problem definition, approach, algorithm, code implementation, complexity analysis, edge cases, and testing. Understanding and solving such problems is crucial for improving coding skills and preparing for technical interviews.
For further reading and practice, consider the following resources: